Answer:
B. Q' (1, 2)
Step-by-step explanation:
im good like that :)
also you can just count how far the Q is from P and R idk how to explain
Upon a slight rearrangement this problem gets a lot simpler to see.
x^3-x+2x^2-2=0 now factor 1st and 2nd pair of terms...
x(x^2-1)+2(x^2-1)=0
(x+2)(x^2-1)=0 now the second factor is a "difference of square" of the form:
(a^2-b^2) which always factors to (a+b)(a-b), in this case:
(x+2)(x+1)(x-1)=0
So g(x) has three real zero when x={-2, -1, 1}
Answer:
yes
Step-by-step explanation:
Answer: 4.5
Step-by-step explanation:
I hope this helps I haven’t done dot plots since 6th grade which was 2 years ago so I’m not confident in my answer
