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Elza [17]
3 years ago
11

IT COST $9 TO GO TO PETE'S POTTERY PLACE TO MAKE YOUR OWN BOWLS $3 PER BOWL. NATALIE GOES TO PETE'S POTTERY PLACE AND MAKES B BO

WLS. SHE DECIODES TO MAKE BOWLS 5 DAYS THIS MONTH SO SHE CAN SELL THEM AT A CRAFTS FAIR.
Part B: If she makes 4 bowls each each time she goes to pete's pottery place, what will her total cost be?
Mathematics
1 answer:
S_A_V [24]3 years ago
8 0
C= 5(9*3b)
C= 5(9*12)
C= 5(108)
C=540
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Graph the equation 5x+2y=10
7nadin3 [17]
Desmos graphing calculator is a very helpful tool!

 <span>5x+2y=10: Displayed in the image below

</span>

6 0
3 years ago
What is the volume of a rectangular prism with a length of 7m, a hight of 9m and a width of 11m
vazorg [7]
Hello!

To find the Volume of the Rectangular Prism, you'll need to multiply all of the measurements together. So you'll need to multiply 7, 9, and 11 together.

V=7*9*11

First, you'll need to multiply 7 and 9. Once you've multiplied 9 and 7 together, you should have 63. Now you should multiply 63 and 11 together. Once you've multiplied 63 and 11 together, you should have a Volume of 693

You should have a Volume of 693m³

I hope this helps!
5 0
3 years ago
For Xavier's lemonade recipe, 6 lemons are required to make 4 cups of lemonade. At what rate are lemons being used in cups of le
dusya [7]

Answer:

Since 6 lemons are used to make 4 cups of lemonade, then are used \frac{6}{4} =\frac{3}{2} of lemon per cup of lemonade, or are make \frac{4}{6}=\frac{2}{3} cups of lemonade per lemon.

7 0
3 years ago
Find a quadratic equation whose roots are 1.5 +√2 and 1.5-√2expressing it in the form of ax^2+bx+c+c=0 where a,b and c are integ
Ilia_Sergeevich [38]

0 = f(x) = (x - r)(x - s) = x² - (r+s) + rs

We have r=1.5+√2,  s=1.5 -√2 so r+s = 3 and

rs = (1.5+√2)(1.5 - √2) = 1.5² - (√2)² = 2.25 - 2 = 0.25

f(x) = x² - 3x + -.25

For integer coefficients we mulitply by 4,

g(x) = 4f(x) = 4x² - 12x - 1

Answer:  4x² - 12x - 1 = 0

5 0
3 years ago
Given that (in picture)...
GuDViN [60]
<h3>Answer:  a = -3 and b = 5</h3>

=================================================

Work Shown:

Multiply top and bottom by \sqrt{2} to rationalize the denominator

\frac{10-\sqrt{18}}{\sqrt{2}}\\\\\frac{\sqrt{2}(10-\sqrt{18})}{\sqrt{2}*\sqrt{2}}\\\\\frac{\sqrt{2}*10-\sqrt{2}*\sqrt{18}}{\sqrt{2*2}}\\\\\frac{\sqrt{2}*10-\sqrt{2*18}}{\sqrt{4}}\\\\\frac{10\sqrt{2}-\sqrt{36}}{2}\\\\\frac{10\sqrt{2}-6}{2}\\\\\frac{-6+10\sqrt{2}}{2}\\\\\frac{2(-3+5\sqrt{2})}{2}\\\\-3+5\sqrt{2}\\\\

We end up with something in the form a+b\sqrt{2} where a = -3 and b = 5

7 0
2 years ago
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