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Assoli18 [71]
3 years ago
7

If the relative frequencies are 0.48 and 0.52, which

Mathematics
2 answers:
balandron [24]3 years ago
8 0

Answer: D

Step-by-step explanation:

frosja888 [35]3 years ago
3 0

Answer:The Last One

Step-by-step explanation:

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Help asap please lol
VARVARA [1.3K]

Answer:

<em>m∠A = 24° , a ≈ 26 ft , b ≈ 51 ft</em>

Step-by-step explanation:

4 0
2 years ago
Please answer this correctly
dlinn [17]

Answer:

The blue ribbon would be the answer if im correct

6 0
4 years ago
Read 2 more answers
Question 4<br> 2 pts<br> If a = -3, b = 2 and c = -4 find the value of the expression.<br> a2 +b²
arsen [322]

Answer:

-2

Step-by-step explanation:

Order of Operations: BPEMDAS

Step 1: Define

a2 + b²

a = -3

b = 2

c = -4

Step 2: Substitute and Evaluate

2(-3) + 2²

-6 + 4

-2

4 0
3 years ago
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Quarters are currently minted with weights normally distributed and having a standard deviation of 0.065. New equipment is being
Ilya [14]

Answer:

Yes, the new equipment appear to be effective in reducing the variation of​ weights.

Step-by-step explanation:

We are given that Quarters are currently minted with weights normally distributed and having a standard deviation of 0.065.

A simple random sample of 25 quarters is obtained from those manufactured with the new​ equipment, and this sample has a standard deviation of 0.047.

Let \sigma = <u><em>standard deviation of weights of new equipment.</em></u>

SO, Null Hypothesis, H_0 : \sigma \geq 0.065      {means that the new equipment have weights with a standard deviation more than or equal to 0.065}

Alternate Hypothesis, H_A : \sigma < 0.065      {means that the new equipment have weights with a standard deviation less than 0.065}

The test statistics that would be used here <u>One-sample chi-square</u> test statistics;

                           T.S. =  \frac{(n-1)s^{2} }{\sigma^{2} }  ~ \chi^{2}__n_-_1

where, s = sample standard deviation = 0.047

           n = sample of quarters = 25

So, <u><em>the test statistics</em></u>  =  \frac{(25-1)\times 0.047^{2} }{0.065^{2} }  ~  \chi^{2}__2_4   

                                     =  12.55

The value of chi-square test statistics is 12.55.

Now, at 0.05 significance level the chi-square table gives critical value of 13.85 at 24 degree of freedom for left-tailed test.

Since our test statistic is less than the critical value of chi-square as 12.55 < 13.85, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u><em>we reject our null hypothesis</em></u>.

Therefore, we conclude that the new equipment have weights with a standard deviation less than 0.065.

5 0
3 years ago
12 ft<br> 9 ft<br> )) What is the length of the hypotenuse?
Lynna [10]
Use pythagorean theorem
a^2 + b^2 = c^2
fill in known values
12^2+9^2 =c^2
simplify
144 + 81 = c^2
225 =c^2
square both sides
15 = c= hypotenuse
7 0
4 years ago
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