Think of integers that have a sum (addition) of 8 that don't include negative integers.
4+4=8
6+2=8
5+3=8
Pat is right there are three different pairs of integers that can have a sum of 8.
Answer:
F. 20(3a-10)^2
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Step-by-step explanation:
180a^2-1200a+2000
Start by looking for a common factor: In this case, it's 20
From here, divide 20 from every number
180a^2/20= 9a^2
1200a/20= 60a
2000/20= 100
You end up with:
20(9a^2-60a+100)
But you can still simplify (9a^2-60a+100)
(9a^2-60a+100) simplifies to (3a-10)^2
So the answer is:
20(3a-10)^2
Answer:
Numbers of students at a primary school before= 240
Number of increased students =42
Again,
Increased number of students in percent(%)= 42/240×100%= 17.5%
Therefore 17.5% students are increased this year.
Answer:
Third grade secondary = 87 students
Step-by-step explanation:
First grade = 30/100 x 250 = 75 students
Second grade = 35/100 x 250 = 87.5 rounded off to 88 students. Because students can't be half thus can't be in decimal. So round off to the nearest whole number.
Third grade = 250 - 88 - 75 = 87 students
The question is asking us to find the sum. To do this, let's first write the original equation and then take it from there.
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Use distributive property:
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Combine Like Terms:
Therefore, the answer to your question is
-4x² + 3x + 4. Hope this helps and have a fantastic day!
