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KatRina [158]
3 years ago
8

In a GP the second and fourth terms are 0.04 and I respectively find the common ratio and the first term​

Mathematics
1 answer:
Reptile [31]3 years ago
4 0

Answer:

common ratio=0.5, a1= 0.08

Step-by-step explanation:

r=a3/a2

r=a4/a3

compare both we get:

a3/a2=a4/a3

subtitute a2=0.04 and a4=1

a3/0.04=1/a3

(a3)^2=0.04*1

(a3)^2=0.04

taking square root in both sides

a3=0.02

For r, r=a3/a2

subtitute a3 and a2 above

r=0.02/0.04

r=0.5 common ratio

For a1

r=a2/a1

0.5=0.04/a1

a1=0.04/0.5

a1=0.08

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Dorothy and Rosanne are baking cookies for a party. Working alone, Rosanne can finish the cookies in 6 hours. Dorothy can finish
garik1379 [7]

Answer:

It will take them 3.43 hours.

Step-by-step explanation:

Let T denote the total cookies that need to be cocked. Observe that:

  1. If Rosanne finishes the cookies in 6 hours, that means that she can make \frac{T}{6} cookies per hour.
  2. If Dorothy finishes the cookies in 8 hours, that means that she can make \frac{T}{8} cookies per hour.

Then, by 1) and 2), if they work together would we able to make

\frac{T}{6}+\frac{T}{8}=\frac{8T+6T}{48}=\frac{14}{48}T=\frac{7}{24}T

cookies per hour.

Therefore, in order to finish the T cookies they will need \frac{24}{7}\approx3.43 hours

3 0
4 years ago
Victor spend a total of 33 picture and text messages which cost 8.30.if text message rate is .18 per message and the picture mes
malfutka [58]
Ok so

t=number of text messsages
p=number of picture messages

total number is 33
t+p=33

if text is 0.18 per pic and picture is 0.45 per text
total cost is 8.3
0.18t+0.45p=8.3
times 100 both sides for ease
18t+45p=830



we now have 2 equations
t+p=33
18t+45p=830

multiply first equation by -18 and add to second equation

18t+45p=830
<span>-18t-18p=-594 +</span>
0t+27p=236

27p=236
divide both sides by 27
p=8.740740740740744
this is impossible becasue you can't send 0.740740740740744 of a message so you did a mistype somewhere
7 0
3 years ago
NEED HELP QUICK!! :)
Vlada [557]
Let x and y be your two consecutive whole numbers

x < sqrt(142) < y
x^2 < 142 < y

So, we are looking for x and y such that x^2 < 142 and y^2 > 142.

The closest squared number to 142 is 144 = 12^2.
Next is 11^2 = 121.

11 and 12 are consecutive.

11^2 = 121 < 142 < 144 = 12^2

Thus, 11 and 12 are your numbers

8 0
3 years ago
8.
Rudiy27

Answer:

B. 1.0

Step-by-step explanation:

I got it right on the quiz

8 0
3 years ago
Read 2 more answers
Azul used a number cube with the numbers 1–6 in a simulation. He signed 1–4 as a favorable outcome and 5–6 as the unfavorable ou
enyata [817]
Answer: The correct choice for this problem is answer D.

In the beginning Azul is describing probability with a number cube. A number cube has 6 possibilities. He labels 4 of them as favorable, 4/6 or 2/3. He labels 2 of them unfavorable, 2/6 or 1/3.

Choice D is the only choice that has a matching probability of 2/3.
7 0
3 years ago
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