Answer:
They all have 90 degrees angles and they have the same width and height they are just on different sides
Step-by-step explanation:
The answer to the question
Answer:
Step-by-step explanation:
f * g = (x^2 + 3x - 4) (x+4)
open bracket
x((x^2 + 3x - 4) + 4 (x^2 + 3x - 4)
x³ +3x²-4x+x²+12x-16
x³+3x²+x²-4x+12x-16
x³+4x²+8x-16 (domain is all real numbers.
f/g = (x^2 + 3x - 4)/(x+4)
factorising (x^2 + 3x - 4)
x²+4x-x_4
x(x+4) -1 (x+4)
(x+4)(x-1)
f/g = (x^2 + 3x - 4)/(x+4) =(x+4)(x-1)/(x+4) = (x-1)
Before factorisation, this was a rational function so the domain is all real numbers excluding any value that would make the denominator equal zero.
Hence I got x - 1, and x cannot equal -4
So the domain is just all real numbers without -4
Answer:
HL (Hypotenuse Leg)
Step-by-step explanation:
You have BC=CD (Because of reflexive property), AC=DC, and measure of BAC is equal to the measure of BDC, which is 90 degrees. Since these triangles are right and they have a hypotenuse and a leg congruent, you can say that they are congruent because of HL.
Six billion three hundred ninety-two million ninety-four thousand and three
