Question

The equation of the circle with center (3, -2) and radius 7 is:

Answer 1

Answer:

$(x-3)^{2}+(y+2)^{2}=49$

Step-by-step explanation:

The center-radius form of the equation of a circle is in the format;

$(x-h)^{2}+(y-k)^{2}=r^{2}$

with the center being at the point (h, k) and the radius being r units.

We simply plugin the values of the center and radius given in order to determine the equation of the circle;

The equation of the circle with center (3, -2) and radius 7 is;

$(x-3)^{2}+(y+2)^{2}=49$

Answer 2

Answer:

$(x-3)^2 + (y+2)^2 = 49$

Step-by-step explanation:

The general equation of a circle has the following form:

$(x-h)^2 + (y-k)^2 = r^2$

Where the point (h, k) represents the center of the circle and r represents the radius

In this case we know that the center is (3, -2) and the radius is 7.

Therefore:

$h=3\\k = -2\\r=7$

Finally the equation of the circle is:

$(x-3)^2 + (y-(-2))^2 = 7^2$

$(x-3)^2 + (y+2)^2 = 49$