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bogdanovich [222]
3 years ago
8

Show that the angles of an equilateral triangle are 60°

Mathematics
1 answer:
Nookie1986 [14]3 years ago
6 0
Equilateral triangle has all sides equal.For triangles sum of interior angle=180degrees
since for equilateral all sides are equal then let x represent the sides
x + x + x = 180deg
3x = 180
x =  \frac{180}{3}  = 60
hence angle of equilateral triangle is 60

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I’ll mark youyou brainlist <br><br> I’ll mark youyou brainlist
alexira [117]

Answer:

31°

Step-by-step explanation:

90° - 59° = 31°

31° + 59° = 90°

4 0
3 years ago
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For each sequence, find the first 4 terms and the 10th term<br> 1) 2n-1
Katena32 [7]

Answer:

1st term: 1, 2nd term: 3, 3rd term: 5, 4th term: 7 & 10th term: 19

Step-by-step explanation:

1st term: 2(1) - 1

              2 - 1 = 1

2nd term: 2(2) - 1

                4 - 1 = 3

3rd term: 2(3) - 1

               6 - 1 = 5

4th term: 2(4) - 1

               8 - 1 = 7

10th term: 2(10) -1

                20 - 1 = 19

6 0
3 years ago
What is the least common multiple of 26 and eight
Anestetic [448]

GCF(8,26) = 2

LCM(8,26) = ( 8 × 26) / 2

LCM(8,26) = 208 / 2

LCM(8,26) = 104

5 0
3 years ago
A membership committee of three is formed from four eligible members. Let the eligible members be represented by A, B, C, and D.
yKpoI14uk [10]

The correct statement is:

  • There are four ways to choose the committee.
  • There are three ways to form the committee if person D must be on it.
  • If persons B and C must be on the committee, there are two ways to form the committee.

It is given that:

A membership committee of three is formed from four eligible members.

1) There are four ways to choose the committee.

This statement is true.

Since we have to choose 3 members out of the 4 members so we can use the method of combination.

2) There are three ways to form the committee if person D must be on it.

This statement is also true.

Since D has to be in the committee, this means we have to choose 2 more people out of the three people to form the committee.

3) If seven members are eligible next year, then there will be fewer combinations.

This statement is wrong.

Since we have to choose 3 members out of 7 members so the number of possible combinations will be:

There are 35 combinations possible.

4) If persons B and C must be on the committee, there are two ways to form the committee.

If B and C have to be in the committee then we have to choose just one person out of the two people left.

Hence, the statement is true.

5) If persons A and C must be on the committee, then there is only one way to form the committee.

If A and C have to be on the committee then as in the last option we have to choose any one of the two-person left.

So possible number of ways is 2.

Hence, the statement is false.

Learn more about committee here: brainly.com/question/425830

#SPJ4

<em>Your question is incomplete. Please read below to find the missing content.</em>

<em />

A membership committee of three is formed from four eligible members. Let the eligible members be represented by A, B, C, and D. The possible outcomes include S = {ABC, ABD, ACD, BCD}.

Which statements about the situation are true? Check all that apply.

There are four ways to choose the committee.

There are three ways to form the committee if person D must be on it.

If seven members are eligible next year, then there will be fewer combinations.

If persons B and C must be on the committee, there are two ways to form the committee.

If persons A and C must be on the committee, then there is only one way to form the committee.

8 0
2 years ago
Sally has 6 boxes of colored pencils only three of the boxes contain 12 colored pencils each .the remaining boxes each contain 2
Sonja [21]
3 times 12 then 3 times 20
3 x 12 = 36
3 x 20 = 60
60 + 36 = 96
96 ÷ 8
3 0
3 years ago
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