Let
x = first integer
y = second integer
z = third integer
First equation: x + y + z = 194
Second equation: x + y = z + 80
Third equation: z = x - 45
Let's find the values of x, y and z.
Substitute 3rd eq to 1st eq:
x + y + x - 45 = 194
2x + y = 45 + 194
y = -2x + 239
Plug in both we have solved for y and the 3rd eq to the 2nd eq to find x
x + (-2x + 239) = (x - 45) + 80
x - 2x - x = -45 + 80 - 239
-2x = -204
x = -204/-2
x = 102
Solving for y,
y = -2(102) + 239
y = 35
Solving for z,
z = 102 - 45
z = 57
Answer:
I believe that the answer is C because it seems to be the only reasonable answer , but i may be wrong , if i am correct please mark the brainliest
Step-by-step explanation
Answer:
x=12
Answer:
(y-2)÷3=x
Step-by-step explanation:
y=3x+2
y-2=3x
(y-2)÷3=x
This answer could also be written as a fraction: y-2 over 3, equals x.
Answer: The answer is -3 1/2 - 1/5
so it's C.
Step-by-step explanation:
Answer:
y-2=9(x+3)
Step-by-step explanation:
y-y1=m(x-x1)
y-2=9(x-(-3))
y-2=9(x+3)
