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Maksim231197 [3]
3 years ago
5

shape ABCDEF is an irregular hexagon. prove that the sum of the shape is720 degrees. show ur working. (3marks)​

Mathematics
1 answer:
guajiro [1.7K]3 years ago
8 0

Answer:

Here's one way to do it  

Step-by-step explanation:

Divide the hexagon into triangles, for example, as in the diagram below.

The triangles are all inside the hexagon, so the sum of their interior angles is the sum of those of the hexagon.

The sum of the interior angles of a triangle is 180°.

There are four triangles, so

Sum of interior angles = 4 × 180° = 720°

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Always use the inverse (opposite) operation.  Ex. is 2x+4=10.

First subtract 4, and then divide by 2.  

actually reverse of order of operations to solve.
4 0
3 years ago
Out of 360 students, 315 went on the class field trip. What percent of students did not go on the class field trip.
astraxan [27]

315 did

therefore

360-315=45 didnt

45/360 students didnt go on the trip

so to turn this into a percentage, just multiply this fraction by 100:

45/360*100 = 12.5%

6 0
2 years ago
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Define the opposite and the absolute value of 6
Archy [21]
Hello : 
<span>the opposite is : -6 
</span><span>the absolute value is : 6</span>
8 0
3 years ago
Prove the polynomial identity (a-1)^3 + (a-1)^2 = a(a-1)^2
Sav [38]

Answer:

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Step-by-step explanation:

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7 0
2 years ago
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When running a 100 meter race Bill reaches his maximum speed when he is 45 meters from the starting line and 5 seconds have elap
Mkey [24]

Bill's speed is constant after 5 seconds and 45 meters into the race.

Correct responses:

a. Bill's maximum speed is 8 m/s

b. 24 meters

c. 57 meters

<h3>Methods used to calculate speed and distance traveled</h3>

Given parameters are;

The distance of the race = 100 meter

Distance at which Bill reaches maximum speed = 45 meters

Speed Bill maintains after 5 seconds = The maximum speed

Time at which Bill is 85 meters from the starting line = 10 seconds after start

a. Required;

Bill's maximum speed in meters.

Solution:

Distance Bill runs at maximum speed, d = 85 m - 45 m = 40 m

Time at which Bill runs the 40 m at maximum speed, <em>t</em> = 10 s - 5 s = 5 s

Speed = \mathbf{\dfrac{Distance}{Time}}

Therefore;

  • Bill's \  maximum \ speed = \dfrac{40 \ m}{5 \ s} = \underline{8 \ m/s}

b. i. Required:

The distance Bill will run for 3 seconds at the maximum speed;

Solution:

Distance,<em> s</em> = Speed, <em>v</em> × Time, <em>t</em>

<em />

The distance traveled at maximum speed in 3 seconds is therefore;

Distance = 8 m/s × 3 s = 24 m

The distance Bill travels in 3 seconds at the maximum speed is 24 meters.

ii) The distance Bill travels at 8 seconds after start, is given as follows;

Distance traveled in the first 5 seconds = 45 meters

Distance traveled in the next 3 seconds = 24 meters

Therefore;

  • Bill's distance from the starting line 8 seconds after start is 45 meters + 25 meters = <u>69 meters</u>

c. Bill's distance 6.5 seconds after the start of the race is given as follows;

Distance traveled in the first 5 seconds = 45 meters

Distance traveled in the next 1.5 seconds = 1.5 s × 8 m/s = 12 meters

  • Bill's distance from the starting line 6.5 seconds after start of the race = 45 meters + 12 meters = <u>57 meters</u>

Learn more about distance, speed, time, relationship here:

https://brainly.in/question/49075584

6 0
2 years ago
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