Question

Find the distance traveled in 15 seconds by an object moving with a velocity of v(t)=20 + 7cost feet per second

Answer 1

Answer:

401.421 feet

Step-by-step explanation:

Given :$v(t)=20 + 7cos t$

To Find : Find the distance traveled in 15 seconds by an object

Solution:

Equation :$v(t)=20 + 7cos t$

where v is the speed and t is the time

Substitute t = 15

$v(15)=20 + 7cos(15)$

$v(15)=26.7614$

So, Speed = 26.7614 feet / second

Time = 15 seconds

Distance = $Speed \times Time$

Distance = $26.7614\times 15$

Distance = 401.421 feet

Hence the distance traveled in 15 seconds by an object moving with a velocity of$v(t)=20 + 7cos t$ feet per second is 401.421 feet

Answer 2

replace 15 for t in the equation

V915) = 20 + 7 cos(15) = 26.76148078 feet per second

26.76148078 x 15 = 401.4222118 feet

 round off to 401.42 feet