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Alex73 [517]
3 years ago
11

Please help me !!!!!!!

Mathematics
1 answer:
umka21 [38]3 years ago
8 0
\frac{2}{3}y+15=9 \ \ \  \ \ \  \ \ \ \  \ \ \ \ \ \ \ \ \ \ \ \ \text{Given} \\\\  \frac{2}{3}y+15-15=9-15 \ \ \ \ \ \ \ \ \text{Subtraction property}  \\  \\ \frac{2}{3}y=-6 \ \ \  \ \ \  \ \ \ \  \ \ \ \ \ \ \ \ \ \ \ \ \ \  \ \ \text{Simplification}  \\  \\ \frac{2}{3}y \cdot \frac{3}{2} =-6\cdot \frac{3}{2} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \  \ \ \text{Multiplication property} \\\\ y=-9 \ \  \ \ \  \ \ \  \ \ \ \  \ \ \ \ \ \ \ \ \ \ \ \ \ \  \ \ \text{Simplification}
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3 years ago
Find the point(s) of intersection (if any) of the plane and the line. Also, determine whether the line lies in the plane. 2x - 2
s2008m [1.1K]

Answer:

the intersection is the point P=(x,y,z)=(8,9,14) and the line does not lie in the plane

Step-by-step explanation:

from the equation of the line

x - 1/2 = y + (3/2)/-1 = (z + 1) / 2  = t (parameter)

then the parametric equation of the line is

x= 1/2 +t

y =  (3/2) + t

z = (-1) + 2*t

therefore from the equation of the plane

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t= 15/2

therefore there is only one intersection of the line with the plane ( then the line does not lie in the plane , since there would be infinite intersection points). The intersection is

x= 1/2 +t = 1/2 +15/2 = 8

y =  (3/2) + t = (3/2) + 15/2 = 9

z = (-1) + 2*t =  (-1) + 2*15/2  = 14

thus the intersection point P=(x,y,z)=(8,9,14)

7 0
3 years ago
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