<h3>I'll teach you how to solve (81x^-20 y^-16)^-3/4</h3>
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(81x^-20 y^-16)^-3/4
Apply exponents rule:
(81x^-20 y^-16)^-3/4=
1 / (81x^-20 y^-16)^-3/4
Simplify (81x^-20 y^-16)^-3/4:
1/27/x^15 y^12
Apply the fraction rule:
x^15 y^12 / 27
Your Answer Is x^15 y^12 / 27
plz mark me as brainliest if this helped :)
This item can be solved by the probability theorem called Bayes' theorem which states that the probability of event A occurring given event B is equal to,
P(A/B) = P(A)P(B/A) / P(B)
where P(B/A) is the probability that the test will yield positive if the person has the disease. P(A) is the probability will be present in any particular person which is equal to 0.04.
P(B) is the probability of positive result irrespective of whether the disease is present of not is calculated below.
P(B) = (0.94)x (0.04) + (0.06)(0.96) = 0.0952
Now, solving for P(A/B)
P(A/B) = (0.94)(0.04) / 0.0952 = 0.039
Thus, the answer is approximately 4%.
A line segment is a line with two end points. Hope this helped! Good luck! :)
I believe the answer is A
