Can you explain how the 1.a equals 14/50

Mathematics

1 answer:

gogolik [260]3 years ago

8 0

First thing you have to do is divide up the 3 columns on the right so that all of the squares are the same size. (I did that in black, you can see it on the picture I attached). Then total all of the little squares. I did this in red, and got 50. Now just count up how many of the lighter colored squares you have, I highlighted them in yellow on my picture. I got 14 light squares. So you end up with fourteen light squares out of 50 total squares, which is 14/50. *apologizes for the bad handwriting on the image I did it on phone. If that didn’t help just comment and let me know what’s still unclear.

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Using the following set of data, calculate the lower quartile, the upper quartile, and the interquartile range. 20, 22, 25, 28,

irina [24]

See the attached picture:
1st find the median, which would be the middle of the data set. Since there are 9 numbers the median would be the middle number of the set, this would give you the same amount of numbers on each side of it. The numbers to the left would be the lower and the numbers on the right would be the upper
so in the given data set the median is 29

the lower quartile is the median of the lower numbers, in this case the numbers below 29 are 20, 22 , 25, 28
since there is an even amount of numbers you need to add the 2 middle numbers together and divide by 2 to find the lower quartile so 22 +25 = 47, 47 / 2 = 23.5 this is the lower quartile
the upper quartile is found the same way, but using the upper numbers so in this case using 30, 32, 33 , 34
add the 2 middle numbers 32 +33 = 65 divide by 2 = 65/ 2 = 32.5 this is the upper quartile
the inter quartile range is subtracting the lower quartile from the upper quartile: 32.5 - 23.5 = 9
9 is the inter quartile range