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2 years ago

How to see if your computer has bluetooth?

1 answer:

3 0

Assuming you're running Windows, click the start button, and then search for "Device Manager" (or open CMD or PowerShell and type devmgmt.msc). Look at the list of devices. If Bluetooth is there, you have it; if it's not there, you don't.

You might be interested in

Assign a variable solveEquation with a function expression that has three parameters (x, y, and z) and returns the result of eva

larisa [96]

Answer:

<em>The programming language is not stated;</em>

<em>However, the program written in Python is as follows</em>

def solveEquation(x,y,z):

result = z - y + 2 * x

print(result)

x = float(input("x = "))

y = float(input("y = "))

z = float(input("z = "))

print(solveEquation(x,y,z))

Explanation:

This line defines the function solveEquation

def solveEquation(x,y,z):

This line calculates the expression in the question

result = z - y + 2 * x

This line returns the result of the above expression

print(result)

The next three lines prompts user for x, y and z

x = float(input("x = "))

y = float(input("y = "))

z = float(input("z = "))

This line prints the result of the expression

print(solveEquation(x,y,z))

3 0

2 years ago

41. All the following software are examples of operating systems EXCEPT

Hunter-Best [27]

Answer:

vista

Explanation:

the other three I have used before

8 0

2 years ago

2. Consider a 2 GHz processor where two important programs, A and B, take one second each to execute. Each program has a CPI of

allsm [11]

Answer:

program A runs in 1 sec in the original processor and 0.88 sec in the new processor.

So, the new processor out-perform the original processor on program A.

Program B runs in 1 sec in the original processor and 1.12 sec in the new processor.

So, the original processor is better then the new processor for program B.

Explanation:

Finding number of instructions in A and B using time taken by the original processor :

The clock speed of the original processor is 2 GHz.

which means each clock takes, 1/clockspeed

= 1 / 2GH = 0.5ns

Now, the CPI for this processor is 1.5 for both programs A and B. therefore each instruction takes 1.5 clock cycles.

Let's say there are n instructions in each program.

therefore time taken to execute n instructions

= n * CPI * cycletime = n * 1.5 * 0.5ns

from the question, each program takes 1 sec to execute in the original processor.

therefore

n * 1.5 * 0.5ns = 1sec

n = 1.3333 * 10^9

So, number of instructions in each program is 1.3333 * 10^9

the new processor :

The cycle time for the new processor is 0.6 ns.

Time taken by program A = time taken to execute n instructions

= n * CPI * cycletime

= 1.3333 * 10^9 * 1.1 * 0.6ns

= 0.88 sec

Time taken by program B = time taken to execute n instructions

= n * CPI * cycletime

= 1.3333 * 10^9 * 1.4 * 0.6

= 1.12 sec

Now, program A runs in 1 sec in the original processor and 0.88 sec in the new processor.

So, the new processor out-perform the original processor on program A.

Program B runs in 1 sec in the original processor and 1.12 sec in the new processor.

So, the original processor is better then the new processor for program B.

5 0

2 years ago

Due to a fire at ABC Software Solutions, all

zaharov [31]

Answer:

chaos among people who worked in the company.

6 0

1 year ago

10 POINTS

Sunny_sXe [5.5K]

Answer:

True

Explanation:

They want to focus on their customers and their interests, so they market their products to a specific audience. hope this helps :)

4 0

2 years ago