The 'quotient' of something means you'll divide. So the quotient of 3 and 927 is 3 divided by 927, or
. That can be simplified to
.
Answer:
<h2><u><em>
x = 5</em></u></h2>
<u><em></em></u>
Step-by-step explanation:
Solve for x.
5 + (x − 2) = 8
5 + x - 2 = 8
x = 8 - 5 + 2
<u><em>x = 5</em></u>
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5 + (5 − 2) = 8
5 + 5 - 2 = 8
8 = 8
the answer is good
Answer:
The division rule of equality tells you that dividing both sides of the equation by the same (non-zero) number does not change the validity of the equation.
Step-by-step explanation:
The equation can be divided by the coefficient of the log function without changing the value of the log function or its argument. Here, that means it is legitimate to divide both sides by 0.65. The result is approximately ...
9.3076923 = log(0.39)
Unless your problem statement tells you to round the number on the left side of this equation, you should maintain its full precision until you have the final answer to the problem at hand. Most useful scientific or graphing calculators will maintain 8 to 12 digit precision; a good one keeps 32 digits or more.
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<em>Comment on the equation</em>
Of course, this logarithm must be to some base other than 10. We can write the logarithm as a log base "b" and solve for that base. Here, we'll use your value of 9.31 as a stand-in for the full-precision number, just so we don't have to write so many digits. We'll use the full-precision value in the final calculation.
Your log equation is only true if the base of the logarithm is about 0.90378430.
Answer:
4000
Step-by-step explanation:
- Factoring a quadratic equation can be defined as the process of breaking the equation into the product of its factors.
- Factorize the equation by breaking down the middle term.
- Let’s identify two factors such that their sum is 7 and the product is -18.
Sum of two factors = 7 = 9 - 2
Product of these two factors = 9 × (-2) = 18
- Now, split the middle term.
- Take the common terms and simplify.
Thus, (3x - 1) and (2x + 3) are the factors of the given quadratic equation.
- Solving these two linear factors, we get