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olga_2 [115]
2 years ago
9

Suppose we apply a dilation by a factor of 3, centered at the point P to the figure below.

Mathematics
2 answers:
Margaret [11]2 years ago
5 0
Agreed with guy above thanks
algol132 years ago
3 0

Answer:

b. Tessa because the line segment does not pass through the center of dilation and therefore its image is parallel to the pre-image.

Step-by-step explanation:

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Guys Please help<br> This is math
Eva8 [605]

Answer:

9

Step-by-step explanation: replace x with 3 then do 6+ 3

7 0
3 years ago
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What is the solution to the equation 3.6m − 2.7 = −1.8m?
Finger [1]

Answer:

Option B is correct

m = 0.5 is the solution to the equation

Step-by-step explanation:

Given the equation:

3.6m-2.7= -1.8m

Add 2.7 to both sides, we have;

3.6m-2.7+2.7= -1.8m+2.7

Simplify:

3.6m = -1.8m+2.7

Add 1.8 m to both sides we have;

5.4m =2.7

Divide both sides by 5.4 we have;

m = \frac{1}{2} = 0.5

⇒m = 0.5

Therefore, the solution for the given equation is, 0.5

7 0
3 years ago
Read 2 more answers
Complete this sequence 4.15, 6.3, 8.45
Scrat [10]
+2.15.
Explanation: subtract 6.3 by 4.15 = 2.15 so you add 2.15
8 0
3 years ago
Read 2 more answers
An experiment was conducted as a one-way factorial design with K sample means, each based on n scores. What is the number of deg
nordsb [41]

Answer:

The mean squares has d.f (n-1)

Step-by-step explanation:

The total number of degrees of freedom is n-1 as there is only one restriction of computing the grand mean. The d.f for k samples is k-1 beacuase the mean of the sample means must equal the grand mean. Similarly , the d.f for within SS is n-k , due to the k restrictions of computing the k sample means. Hence we find that

Total df= Within df + Between df

n-1=  (n-k)+(k-1)

Between SS has (k-1) d.f

Within SS has (n-k) d.f

These two quantities are known as mean squares and has d.f (n-1)

8 0
3 years ago
EXERC
eimsori [14]

Answer:551.3212cm³

Step-by-step explanation:

Find the image attached

The volume is made up of a cone, cylinder and a hemisphere

Volume of the shape = Volume of cone + volume of cylinder + volume of hemisphere

Get the volume of the cone;

Volume of a cone Vc = 1/3πr²h

r is the base radius = 3.5cm

Height = 10cm

Vc = 1/3π(3.5)²(6)

Vc = 1/3π(12.25)(6)

Vc = 12.25 * 2π

Vc = 24.5π cm³

Get the volume of the cylinder;

Vcy = πr²h

r = 3.5cm

h = 10cm

Vcy = π(3.5)²(10)

Vcy = π(12.25)(10)

Vcy = π(122.5)

Vcy = 122.5π cm³

Get rhe volume of the hemisphere;

Volume of hemisphere = 2/3 πr³

r = 3.5cm

Vh =  2/3 π(3.5)³

Vh = 2/3π(42.875)

Vh = 28.58π cm³

Volume of the shape = VC + Vcy + Vh

Volume of the shape = 24.5π+122.5π+28.58π

Volume of the shape = 175.58π

<em>Volume of the shape = 551.3212cm³</em>

7 0
3 years ago
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