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olga_2 [115]
2 years ago
9

Suppose we apply a dilation by a factor of 3, centered at the point P to the figure below.

Mathematics
2 answers:
Margaret [11]2 years ago
5 0
Agreed with guy above thanks
algol132 years ago
3 0

Answer:

b. Tessa because the line segment does not pass through the center of dilation and therefore its image is parallel to the pre-image.

Step-by-step explanation:

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WILL MARK BRAINLIEST!
Artist 52 [7]

Answer:

Following are the responses to the given points:

Step-by-step explanation:

Dilation implies the triangle \Delta XYZ stretched through the factor "2".  

m\angle Y = m\angle C = 90^{\circ} \leftarrow given \\\\  

right triangles:

\Delta  XYZ and \Delta  ACB \\\\\angle X \cong \angle A \leftarrow given\\\\

complementary angles:  

\angle X \ and\  \angle Z

m\angle Z = 90^{\circ} - m\angle X \\\\

complementary angles:

\angle A \ and\  \angle B

m\angle B = 90^{\circ} - m\angle A \\\\\therefore \\\\ \angle Z \cong \angle B \\\\\Delta  XYZ \sim  \Delta ACB \\\\

Same triangles: proportional side are corresponding, congruence angles are respective.

\sin \angle X = \frac{5}{5.59} \leftarrow given \\\\\sin\angle X = \frac{YZ}{XY} \\\\YZ = 5 (units) \rightarrow leg in \Delta XYZ \\\\XZ = 5.59 (units) \rightarrow hypotenuse \ in\  \Delta XYZ\\\\

Calculating the length of leg XY:

XY = \sqrt{((5.59)^2 - 52)} \cong 2.4996 (units)\\\\\frac{CB}{YZ} = 2 \leftarrow given \\\\CD = 2YZ = 2 \times 5 = 10 \ (units)\\\\\frac{AC}{XY} = 2 \leftarrow  \ given\\\\AC = 2XY \cong 2 \times  2.4996 \cong 4.999\  (units)\\\\

3 0
2 years ago
19.47 is what percent of 29.5
zvonat [6]
<span>19.47 is 66% of 29.5.

hope this helps! :)</span>
7 0
2 years ago
Read 2 more answers
L=a+(n-1)d <br><br> solve for n
earnstyle [38]

Answer:

(L-a)/d + 1 = n

Step-by-step explanation:

Let's isolate (n-1), and after that isolate n:

1) subtract a from both sides:  L - a = (n-1)d

2) Divide both sides by d:  (L-a)/d = n-1

3) Add 1 to both sides, to isolate n:            (L-a)/d + 1 = n

3 0
3 years ago
Which is the equation of a hyperbola centered at the origin with vertex (0, sqrt 12 ) that passes through (2 sqrt 3,6)
mina [271]

Answer:

y-intercept = a +y^2/12 term in it.

Then for y=6, you have

.. 6^2/12 -x^2/b = 1

.. 2 = x^2/b

.. b = x^2/2

If your point is (2√3, 6), then this is

.. b = (2√3)^2/2 = 12/2 = 6

Then the hyperbola's equation is

.. y^2/12 -x^2/6 = 1 . . . . . . . . selection D

Step-by-step explanation:

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3 years ago
each class AT BRIARWOOD ELEMentary collected at least 54 cans during the food drive. If there were 29 classes in the school what
sertanlavr [38]
You multiply 54 by 29 which will leave you with 1566
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