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3 years ago

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Find a formula in n, a, m, and d for the sum (a md) (a (m 1)d) (a (m 2)d) · · · (a (m n)d), where m and n are integers, n ≥ 0, a

nd a and d are real numbers. justify your answer.

1 answer:

Anettt [7]3 years ago

3 0

Write this as the sum of:
a+md
a+md+d
a+md+d+d
...
a+md+d+d+...+d

Total=n(a+md)+d(1+2+3+...+n-1)=n(a+md)+dn(n-1)/2

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When obtaining a confidence interval for a population mean in the case of a finite population of size N and a sample size n whic

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Answer:

95% Confidence interval for the mean

$142.8 \leq\mu\leq158.4$

Step-by-step explanation:

We have to calculate a 95% confidence interval for the mean of a finite population.

The error is multiplied by the following finite population correction factor:

$cf=\sqrt{\frac{N-n}{N-1} }$

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The 95% confidence interval has a z value of 1.96, so it becomes:

$M-z*\sigma_c\leq\mu\leq M+z*\sigma_c\\\\150.6-1.96*3.963\leq\mu\leq 150.6+1.96*3.963\\\\ 142.8 \leq\mu\leq 158.4$

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Step-by-step explanation:

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2 years ago

Give EG = 5x+7 EF =5x and FG=2x-7

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Answer:

x = 7

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EG = 5x+7
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Step-by-step explanation:

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<u>When n is 15:</u>

n + 6 = 21
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<u>When n is 21:</u>

n + 6 = 27
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<em>Thus, the expression is proven correct. Now, let's find n + 6 when n is 28.</em>

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Answer:

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2 years ago

Read 2 more answers