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madreJ [45]
3 years ago
13

Please tell me the correct answer. If u answer correct I’ll mark u as brainiest. I really need help.

Mathematics
1 answer:
liq [111]3 years ago
3 0

Answer:

b

Step-by-step explanation:

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Sally has only nickels and dimes in her money box. She knows that she has less than $20 in the box. Let x represent the number o
Aleonysh [2.5K]

The statement which best describes the steps to graph the solution to the inequality in x and y is the third option from the scale, because :


x nickels = 5x cents


y dimes in turn - 10y cents. 


Multiply them together and now we have  5x + 10y cents. 


Total amount sloud be less than $20 or 2000 cents. 


Read more on Brainly.com - brainly.com/question/1870318#readmore

8 0
3 years ago
Sixety five divided by fifteen ​
oee [108]

Answer:

the answer is 4 with a remainder of three

7 0
2 years ago
20 POINTS!!!
Makovka662 [10]

Answer:

Step-by-step explanation: this problem will result in difference of two squares.

Firstly since they are both areas, it will be area of the bigger square minus area of the smaller squares.

52² - 32²= (52+32)(52-32)

= (84)(20)

=1680inch².

Therefore the area of the material that will remain uncovered will be

1680inches²

5 0
3 years ago
Read 2 more answers
What is the degree of the polynomial expression 4khrn
sergejj [24]
IDK IDK IDK IDK I DONT KNOW
8 0
3 years ago
The slope of EF¯¯¯¯¯ is −52.
9966 [12]

Based on the above, the segments that are perpendicular to EF are LM and NP.

<h3>Why is the segment are LM and NP perpendicular  to EF ?</h3>

Note that when two lines are perpendicular, we can say that;

M1 * M2 = -1 As M1 and M2 are known to be the slopes of the lines.

Therefore, when the the slope of EF is said to be −5/2, then  one can say that the slope of  the segment that is said to be  perpendicular to EF will have to be equal to m1*m2=-1, m2=-1/m1, m2=-1/(-5/2) or m2=2/5.

Scenario one:

JK , if J is at (3, −2) and K is at (5, −7)

To find the slope JK, then

m=(y2-y1)/x2-x1)

m=(-7+2)/(5-3)

m=-5/2

-5/2 is not equal to 2/5

Therefore,  JK is not perpendicular to EF

Scenario 2

Find GH , when G is at (6, 7) and H is at (4, 12)

To find the slope GH

m=(y2-y1)/x2-x1)

m=(12-7)/(4-6)

m=5/-2

m=-5/2

Since -5/2 is not equal to 2/5 then GH is not perpendicular to EF

Scenario 3:

Find LM , If L is at (1, 9) and M is at (6, 11)

To find the slope LM, then

m=(y2-y1)/x2-x1)

m=(11-9)/(6-1)

m=2/5

Since 2/5 is equal to 2/5

Then LM is perpendicular to EF

Scenario 4:

Find NP , if N is at (−3, 4) and P is at (−8, 2)

To find the slope NP, then

m=(y2-y1)/x2-x1)

m=(2-4)/(-8+3)

m=-2/-5

m=2/5

Since 2/5 is equal to 2/5.

Therefore,  NP is perpendicular to EF

Based on the above calculations, the segments that are perpendicular to EF are LM and NP.

See correct format of question written below

The slope of EF is −5/2 .

Which segments are perpendicular to EF?

Select all the right answers please

1. JK , where J is at (3, −2) and K is at (5, −7)

2. GH , where G is at (6, 7) and H is at (4, 12)

3. LM , where L is at (1, 9) and M is at (6, 11)

4. NP , where N is at (−3, 4) and P is at (−8, 2)

Learn more about segments from

brainly.com/question/10565562

#SPJ1

5 0
2 years ago
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