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Keith_Richards [23]
3 years ago
9

33.52 is what percent of 8

Mathematics
1 answer:
uysha [10]3 years ago
7 0
.08
8  Divide by 100 equal 0.08
 
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Please help!!!! Describe how you would graph the equation y= -20x + 150.
deff fn [24]
First, plot the y-intercept which is 150. So, plot the point (0,150).
Then, just input values of x into the equation.
Use the value of x you input and y value you got after solving into (x,y) and plot the point.
7 0
3 years ago
What is the constant difference for a hyperbola with foci (-3.5, 0) and (3.5, 0) and a point on the hyperbola (3. 5, 24)?
OLga [1]
I do not understand the question
8 0
3 years ago
1 min to fill 16.50 gallons what is the constant
Klio2033 [76]

Answer:constant is 2/33

Step-by-step explanation:

1 min to fill 16.50 gallons

Time(t) varies directly as volume(v)

t α v

t =k x v Where k is constant

1=k x 16.50

k=1/16.50

k=2/33

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7 0
4 years ago
One batch of muffins require 1/4 cup of sugar. Kelly wants to make 3/2 batch of muffins. Will she use more than, less than, or a
Alla [95]
She will use more than 1/4 cup of sugar to make 1.5 batches of muffins.  If one batch of muffins requires 1/4 cup of sugar, you can think of the amount of sugar needed being 1/4 cup per batch.  That being said multiply 1.5 batches by 1/4 cup per batch to find cups of sugar.
(1.5 batches)x((1/4 cups)/(1 batch))=0.375 cups of sugar.

You can also think of it as if one batch takes 1/4 cup of sugar, half of a batch would take 1/8 cup of sugar.  Since 1.5 batches is just 1 batch+1/2 batch, you can say the amount of sugar needed is 1/4 cup+1/8 cup which equals 3/8 cup sugar.

I hope this helps you.
5 0
3 years ago
If equation of a circle is x^2 + y^2 + 6x + 4y + 10 = 1 What is this equation written in its standard form?
Darya [45]

\text{The equation of a circle in standard form:}\\\\(x-h)^2+(y-k)^2=r^2\\\\(h,\ k)-center\\r-radius\\---------------------------\\\\Use\ (a+b)^2=a^2+2ab+b^2\\\\---------------------------

x^2+y^2+6x+4y+10=0\qquad\text{subtract 10 from both sides}\\\\x^2+6x+y^2+4y=-10\\\\x^2+2x\cdot3+y^2+2y\cdot2=-10\qquad\text{add}\ 3^2\ \text{and}\ 2^2\ \text{to both sides}\\\\(x^2+2x\cdot3+3^2)+(y^2+2y\cdot2+2^2)=-10+3^2+2^2\\\\(x+3)^2+(y+2)^2=-10+9+4\\\\\boxed{(x+3)^2+(y+2)^2=3}

5 0
3 years ago
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