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3 years ago

7

In which sentence is refuge used correctly?

2 answers:

PSYCHO15rus [73]3 years ago

6 0

Theoretically both A and D are correct. Although D is an answer that could possibly make sense, it would not be the most effective refuge. The most accurate answer is <span>
A. We took refuge from the rain by standing inside the doorway. </span>

Tju [1.3M]3 years ago

6 0

Answer:

Option: A

Step-by-step explanation:

<em> Refuge means</em>

a state of safety, protection or shelter.

something or someone turned to for safety or assistance, a recourse or resort

So, According to the definition of the refuge we could see that option: A is clearly correct.

As due to rain we took refuge by standing inside the doorway.

so doorway is the safe place for them so that they won't be disturbed by the rain.

Hence option A is correct.

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sp2606 [1]

So... that's.... U-27... which apparently is negative 15.... so now all I have to do is subtract 15 from 100.... so.... Steve's current balance is now $85.
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3 years ago

1 Evaluate the expression. r3 - 2s if r = 5 and s = 4

user100 [1]

Answer:

117

Step-by-step explanation:

Given the expression

r³ - 2s ← substitute given values into the expression

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= 125 - 8

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3 years ago

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jeka57 [31]

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3 years ago

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2 years ago

Suppose box A contains 4 red and 5 blue poker chips and box B contains 6 red and 3 blue poker chips. Then a poker chip is chosen

sergejj [24]

Answer:

0.5172 = 51.72% probability a blue poker chip was transferred from box A to box B, given that the coin just chosen from box B is red

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Coin chosen from box B is red.

Event B: Blue poker chip transferred.

Probability of choosing a red coin:

7/10 of 4/9(red coin from box A)

6/10 of 5/9(blue coin from box A). So

$P(A) = \frac{7}{10}*\frac{4}{9} + \frac{6}{10}*\frac{5}{9} = \frac{28 + 30}{90} = 0.6444$

Blue chip transferred, red coin chosen:

6/10 of 5/9. So

$P(A \cap B) = \frac{6}{10}*\frac{5}{9} = \frac{30}{90} = 0.3333$

What is the probability a blue poker chip was transferred from box A to box B, given that the coin just chosen from box B is red?

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.3333}{0.6444} = 0.5172$

0.5172 = 51.72% probability a blue poker chip was transferred from box A to box B, given that the coin just chosen from box B is red

5 0

3 years ago