Answer:
I. First number, a = 40.
II. Second number, b = 50.
III. Third number, c = 120.
Step-by-step explanation:
Let the three numbers be a, b and c respectively.
Given the following data;
Translating the word problem into an algebraic equation, we have;
a + b + c = 210
b = a + 10
c = 3a
Substituting the value of b and c into the equation, we have;
a + a + 10 + 3a = 210
5a + 10 = 210
5a = 210 - 10
5a = 200
a = 200/5
<em>a = 40</em>
To find the value of b;
b = a + 10
b = 40 + 10
<em>b = 50</em>
To find c
c = 3a
c = 3*40
<em>c = 120</em>
x ,y are the numbers
x = 5y-3
x+y = 27
substitute first equation into the second
(5y-3) +y =27
combine like terms
6y-3=27
add 3 to each side
6y=30
divide by 6
y=5
x = 5y-3
x=5*5-3
x=22
the two numbers are 22 and 5
Well there really wouldn't be a combo since everything is different so I'm saying nun? that's what I'm going with. ( If this is wrong correct me )
Answer:
71 remainder 80
Step-by-step explanation:

<h2>HI MATE YOUR ANSWER SHOULD BE 10/3</h2>