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Nookie1986 [14]
2 years ago
6

1000ml:300ml to its simplest form

Mathematics
1 answer:
Diano4ka-milaya [45]2 years ago
5 0
<h2>HI MATE YOUR ANSWER SHOULD BE 10/3</h2>
You might be interested in
3 + x + 1 = 2<br><br> Thank you :)
Lina20 [59]

Answer:

x = -2

Step-by-step explanation:

Please mark Brainliest when able, for showing work.

8 0
3 years ago
Please help asap!!! i dont understand it
pshichka [43]

Answer:

a

Step-by-step explanation:

A perpendicular bisector, intersects a line at its mid point and is perpendicular to it.

Calculate slope m using the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = (- 7, 1) and (x₂, y₂ ) = (9, 13)

m = \frac{13-1}{9-(-7)} = \frac{12}{9+7} = \frac{12}{16} = \frac{3}{4}

Given a line with slope m then the slope of a line perpendicular to it is

m_{perpendicular} = - \frac{1}{m} = - \frac{1}{\frac{3}{4} } = - \frac{4}{3} ←  slope of perpendicular bisector

Given endpoints (x₁, y₁ ) and (x₂, y₂ ) then the midpoint is

(\frac{x_{1}+x_{2}  }{2}, \frac{y_{1}+y_{2}  }{2} )

using (x₁, y₁ ) = (- 7, 1) and (x₂, y₂ ) = (9, 13) , then

midpoint = ( \frac{-7+9}{2}, \frac{1+13}{2} ) = ( \frac{2}{2}, \frac{14}{2} ) = (1, 7 )

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Here m = - \frac{4}{3} , then

y = - \frac{4}{3} x + c ← is the partial equation

To find c substitute the midpoint (1, 7) into the partial equation

7 = - \frac{4}{3} + c ⇒ c = \frac{21}{3} + \frac{4}{3} = \frac{25}{3}

y = - \frac{4}{3} x + \frac{25}{3} ← equation of perpendicular bisector

7 0
3 years ago
Allison is evaluating the expression -5-(-2) using integer tiles. She begins with 5 negative tiles as shown. What should Allison
mote1985 [20]

Answer:

Add 2

Step-by-step explanation:

When distributing, pay attention to the negatives both inside and outside the parentheses. Imagine a 1 directly after the second negative symbol in the equation:

-5-1(-2)

Don't subtract 1 from 5! Instead multiply -1 by -2 (you're distributing, remember?)

A negative multiplied by another negative equals a positive!

-5+2

-5+2=-3

4 0
3 years ago
5. A hot dog and three pickles
taurus [48]
Set h as hotdogs and p for pickles and solve linear systems so like h+3p=6.50
2h+2p=7.00
4 0
3 years ago
A group of students estimated the length of one minute without reference to a watch or​ clock, and the times​ (seconds) are list
alexandr402 [8]

Complete Question

The complete question is shown on the first uploaded image  

Answer:

Yes the students are reasonably good at estimating one​ minute

a

  Option A is  correct

b

  The test statistics is  t  =  0.354

Step-by-step explanation:

From the question we are told that

    The  set of data is  

               68, 82 ,  38 ,  62 , 41, 25 , 57 ,  64, 67, 47, 61, 71, 91, 87, 64

     The  population mean is  \mu  = 60

The  level of significance is given as\alpha =  0.01

    The  critical value for this level of significance obtained from the normal distribution table is  

         Z_{\alpha } =  2.33

   The  null hypothesis is  

           H_o  :  \mu  =  60 \ seconds

   The alternative hypothesis is  

          Ha :  \mu \ne 60 \ seconds      

Generally the sample mean is mathematically represented as

       \= x  =  \frac{\sum x_i }{n  }

where  n = 15

 So  

      \= x  =  \frac{ 68+ 82 +  38 +  62 + 41+ 25 + 57 + 64+67+ 47+ 61+ 71+ 91+ 87+ 64}{15}

      \= x  =  61.67

The standard deviation is mathematically represented as

     \sigma  =\sqrt{  \frac{ \sum  (x_i -  \= x )^2}{n} }

substituting values

      \sigma  =\sqrt{  \frac{ \sum  (68-61.67)^2 + ( 82-61.67 )^2  +   (38 -61.67)^2 +  62-61.67)^2 + (41-61.67)^2 +(25-61.67)^2 +( 57+61.67)^2 }{15} }           \sqrt{  \frac{  ( \cdot  \cdot  + (  64-61.67)^2 + (67-61.67)^2 +(47-61.67)^2 + (61-61.67)^2+  (71-61.67)^2 + (91 -61.67)^2+( 87-61.67)^2 +  (64-61.67)^2}{15} }=>   \sigma  =  18.23

The  test statistics is evaluated as  

      t  =  \frac{\= x  - \mu  }{ \frac{\sigma }{\sqrt{n} } }

substituting values

       t  =  \frac{61.67  -60  }{ \frac{18.23 }{\sqrt{ 15} } }

      t  =  0.354

Now comparing the statistics and the critical value of the level of significance we see that the the test statistics is less than the critical value

Hence the we fail to reject the null hypothesis which mean that these times are from a population with a mean equal to 60 seconds

So we can state that yes the students are reasonably good at estimating one minute given that the sample mean is not far from the population mean

4 0
3 years ago
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