1st,since this GP is convergent that means the common ratio r <1
2nd, sum of a GP = a₁(1-rⁿ)/(1-r), where a₁ = 1st term and n=number of terms
3rd, for any convergent GP, r<1 and the sum of all terms =a₁/(1-r): Why?
[since r<1 → lim rⁿ when n→∞, =0 in the formula of the 2nd)]
Now let's solve :
a) Sum = a₁(1-r³)/(1-r) = 19 (sum of the first 3 terms)
b) Σ(Sum) = a₁/(1-r) = 27 (sum of all terms of this CONVERGENT GP)
Divide a) by b):
[a₁(1-r³)/(1-r)] / [a₁/(1-r)] = 19 /27 ↔ [a₁(1-r³)/(1-r)] x [(1-r)/a₁]=19/27.
Simplify:
(1-r³) = 19/27
-r³ = 19/27 - 1
r³ = 8/27
r = ∛(8/27)
r = 2/3 and a₁ = 9 (Plug r in the Σ sum)
Hence first term a₁ = 9
and common ration r =2/3
4 + 8 + 12 + 4n = 2n(n + 1)
24 + 4n = 2n(n) + 2n(1)
24 + 4n = 2n² + 2n
<u> -2n -2n</u>
24 = 2n²
<u>24</u> = <u>2n²
</u> <u /> 2 2
12 = n²
√12 = n
√4 × 3 = n
√4 √3 = n
2 √3 = n
<u />
The 2 on the end is the thousandths place. In order to know whether it should remain a '2' or increase to a '3', we would need to know what comes after it.
-- If there's nothing after it, then it's already written to the nearest thousandth.
-- If there <em>is</em> more after it, we don't know what that is, so we have nothing to base a decision on.
Answer:
-2,2
Step-by-step explanation:
Let


We have to find the value of c such that the are of the region bounded by the parabolas =32/3






Now, the area bounded by two curves




![\frac{32}{3}=2[c^2x-\frac{4}{3}x^3]^{c/2}_{-c/2}](https://tex.z-dn.net/?f=%5Cfrac%7B32%7D%7B3%7D%3D2%5Bc%5E2x-%5Cfrac%7B4%7D%7B3%7Dx%5E3%5D%5E%7Bc%2F2%7D_%7B-c%2F2%7D)






![c=\sqrt[3]{8}=2](https://tex.z-dn.net/?f=c%3D%5Csqrt%5B3%5D%7B8%7D%3D2)
When c=2 and when c=-2 then the given parabolas gives the same answer.
Therefore, value of c=-2, 2
Answer:
the volume of a cylindrical-shaped corn silo with a height that is 3 times the radius
Step-by-step explanation:
i took test