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Setler [38]
3 years ago
5

Which link between two elements could you remove from the relation so that it becomes a function? 1 and c or 3 and a 4 and d or

5 and d 2 and e or 4 and d 2 and b or 2 and e

Mathematics
2 answers:
shtirl [24]3 years ago
8 0
It would make more sense to remove 4 and D

sertanlavr [38]3 years ago
7 0

Answer: 2 and E or 4 and D

Step-by-step explanation:

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The sum of the first three terms of a convergent geometric series is 19. the sum of the series is 27. find the first term and th
NikAS [45]
1st,since this GP is convergent that means the common ratio r <1
2nd, sum of a GP = a₁(1-rⁿ)/(1-r), where a₁ = 1st term and n=number of terms
3rd, for any convergent GP, r<1 and the sum of all terms =a₁/(1-r): Why?
[since r<1 → lim rⁿ when n→∞, =0 in the formula of the 2nd)]
Now let's  solve :

a) Sum = a₁(1-r³)/(1-r) = 19 (sum of the first 3 terms)
b) Σ(Sum) = a₁/(1-r) = 27 (sum of all terms of this CONVERGENT GP)

Divide a) by b):

[a₁(1-r³)/(1-r)] / [a₁/(1-r)] = 19 /27 ↔ [a₁(1-r³)/(1-r)] x [(1-r)/a₁]=19/27.
Simplify:
(1-r³) = 19/27
-r³ = 19/27 - 1
r³ = 8/27

r = ∛(8/27)

r = 2/3 and a₁ = 9 (Plug r in the Σ sum)
Hence first term a₁ = 9
and common ration r =2/3



4 0
3 years ago
4+8+12+... + 4n=2n(n+1)
Blababa [14]
4 + 8 + 12 + 4n = 2n(n + 1)
            24 + 4n = 2n(n) + 2n(1)
            24 + 4n = 2n² + 2n
           <u>        -2n            -2n</u>
                    24 = 2n²
                    <u>24</u> = <u>2n²
</u>       <u />              2      2
                    12 = n²
                  √12 = n
              √4 × 3 = n
               √4 √3 = n
                 2 √3 = n
<u />
4 0
3 years ago
What is 34,567.992 rounded to nearest thousandth
lesya692 [45]
The  2  on the end is the thousandths place.  In order to know whether it should remain a '2' or increase to a '3', we would need to know what comes after it. 

-- If there's nothing after it, then it's already written to the nearest thousandth.

-- If there <em>is</em> more after it, we don't know what that is, so we have nothing to base a decision on.
4 0
3 years ago
Find the values of c such that the area of the region bounded by the parabolas y = 4x2 − c2 and y = c2 − 4x2 is 32/3. (Enter you
Misha Larkins [42]

Answer:

-2,2

Step-by-step explanation:

Let

y_1=4x^2-c^2

y_2=c^2-4x^2

We have to find the value of c such that the are of the region bounded by the parabolas =32/3

y_1=y_2

4x^2-c^2=c^2-4x^2

4x^2+4x^2=c^2+c^2

8x^2=2c^2

x^2=c^2/4

x=\pm \frac{c}{2}

Now, the area bounded by two curves

A=\int_{a}^{b}(y_2-y_1)dx

A=\int_{-c/2}^{c/2}(c^2-4x^2-4x^2+c^2)dx

\frac{32}{3}=\int_{-c/2}^{c/2}(2c^2-8x^2)dx

\frac{32}{3}=2\int_{-c/2}^{c/2}(c^2-4x^2)dx

\frac{32}{3}=2[c^2x-\frac{4}{3}x^3]^{c/2}_{-c/2}

\frac{32}{3}=2(c^2(c/2+c/2)-4/3(c^3/8+c^3/28))

\frac{32}{3}=2(c^3-\frac{4}{3}(\frac{c^3}{4}))

\frac{32}{3}=2(c^3-\frac{c^3}{3})

\frac{32}{3}=2(\frac{2}{3}c^3)

c^3=\frac{32\times 3}{4\times 3}

c^3=8

c=\sqrt[3]{8}=2

When c=2 and when c=-2 then the given parabolas gives the same answer.

Therefore, value of c=-2, 2

7 0
2 years ago
Identify the word problem that represents the algebraic expression πr²(3r).
Olegator [25]

Answer:

the volume of a cylindrical-shaped corn silo with a height that is 3 times the radius

Step-by-step explanation:

i took test

8 0
3 years ago
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