what is the shape of a cross section that is perpendicular to the base of a cube A. rectangle B. triangle C.square D. circle

Mathematics

1 answer:

777dan777 [17]3 years ago

8 0

Answer:

2qwertfghtrew3eret

Step-by-step explanation:

3ewrew

You might be interested in

Suppose that there are two types of tickets to a show: advance and same-day. Advance tickets cost and same-day tickets cost . Fo

AveGali [126]

Answer:

83746+4747+48484=3943848343

Step-by-step explanation:

Easy

8 0

2 years ago

In the aftermath of a car accident, it is concluded that one driver slowed to a halt in 20 seconds while skidding 1775 feet. If

-Dominant- [34]

Assume uniformly accelerated motion

Vf = Vo - at => a= [Vo - Vf] / t

Vf = 0, t = 20 s => a = Vo / 20

x = Vot - at^2 / 2

x = Vot - (Vo / 20) * t^2 /2

x = 1775 feet * [1 mile / 5280 feet] = 0.336 mile

t = 20 s

=> 0.336 = 20Vo - Vo(20)^2 /(40) = 20Vo - 10 Vo = 10 Vo

=> Vo = 0.336 /10 = 0.0336 mile /s

Vo = 0.0336 mile/s * 3600 s/h = 120.96 mile / h

Therefore, the car was way over the speed limit.

7 0

3 years ago

Qhat is the ratio of 6to 5

asambeis [7]

6:5 is the ratio #answerwithquality #BAL

3 0

3 years ago

How do I solve 3.2x+0.2x^2-5=0

bogdanovich [222]

$3.2x+0.2x^2-5=0\ \ \ \ |both\ sides\ multiply\ by\ 5\\\\16x+x^2-25=0\\\\x^2+16x-25=0\\\\a=1;\ b=16;\ c=-25\\\\\Delta=b^2-4ac\to\Delta=16^2-4\cdot1\cdot(-25)=256+100=356\\\\x_1=\frac{-b-\sqrt\Delta}{2a}\ and\ x_2=\frac{-b+\sqrt\Delta}{2a}\\\\\sqrt\Delta=\sqrt{356}=\sqrt{4\cdot89}=2\sqrt{89}\\\\x_1=\frac{-16-2\sqrt{89}}{2\cdot1}=-8-\sqrt{89};\ x_2=\frac{-16+2\sqrt{89}}{2\cdot1}=-8+\sqrt{89}$

8 0

3 years ago

Ill give the crown things plzz helpppp

Aleks04 [339]

Answer:

Step-by-step explanation:

1st step: 63 divided by 3= 21

2nd step: 63- 21= 42

7 0

3 years ago