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serious [3.7K]
3 years ago
12

9x<-27 or 4x>36 solve for the compound inequality

Mathematics
1 answer:
pochemuha3 years ago
3 0
9x < -27 or 4x > 36
 9       9       4      4
   x < -3         x > 9

x ∈ (-∞, 3) or (9, ∞)
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(1 + 3x)º (x – 13) °
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3x^2-38x-13

Step-by-step explanation:

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Step-by-step explanation:

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Directions: Find the indicated trigonometric ratio as a fraction in simplest form. 1. Sin L =
Rainbow [258]

Answer:

\sin L = 0.60

tan\ N = 1.33

\cos L = 0.80

\sin N = 0.80

Step-by-step explanation:

Given

See attachment

From the attachment, we have:

MN = 6

LN = 10

First, we need to calculate length LM,

Using Pythagoras theorem:

LN^2 = MN^2 + LM^2

10^2 = 6^2 + LM^2

100 = 36 + LM^2

Collect Like Terms

LM^2 = 100 - 36

LM^2 = 64

LM = 8

Solving (a): \sin L

\sin L = \frac{Opposite}{Hypotenuse}

\sin L = \frac{MN}{LN}

Substitute values for MN and LN

\sin L = \frac{6}{10}

\sin L = 0.60

Solving (b): tan\ N

tan\ N = \frac{Opposite}{Adjacent}

tan\ N = \frac{LM}{MN}

Substitute values for LM and MN

tan\ N = \frac{8}{6}

tan\ N = 1.33

Solving (c): \cos L

\cos L = \frac{Adjacent}{Hypotenuse}

\cos L = \frac{LM}{LN}

Substitute values for LN and LM

\cos L = \frac{8}{10}

\cos L = 0.80

Solving (d): \sin N

\sin N = \frac{Opposite}{Hypotenuse}

\sin N = \frac{LM}{LN}

Substitute values for LM and LN

\sin N = \frac{8}{10}

\sin N = 0.80

7 0
3 years ago
Idk what all these means need help plzzzzzx
Schach [20]
It is d bexause every 6 is moved to the left for every one and it isnt abexause if you add 6 it would instwad go 6 12 18 24 and so on and its no c because if you move it to the right the # would decrease and obviously not b because if you subtract 0 every time it would stay as the same number
3 0
3 years ago
Read 2 more answers
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