Answer:
a₂ = -3
a₃ = -1
Step-by-step explanation:
We have to insert two arithmetic means between -5 and 1
Let a₁ and b₂ be the two arithmetic means between -5 and 1
-5, a₂, a₃, 1
Here,
We know that the nth term of an Arithmetic sequence
aₙ = a₁ + (n-1)d
a₄ = -5 + (4-1)d
1 = -5 + 3d
1 + 5 = 3d
3d = 6
Dividing both sides by 2
d = 2
Also
a₂ = a₁ + (2-1)d
a₂ = -5 + d
a₂ = -5 + 2 ∵ d = 2
a₂ = -3
a₃ = a₁ + (3-1)d
a₃ = -5 + 2d
a₃ = -5 + 2(2) ∵ d = 2
a₃ = -5 + 4
a₃ = -1
Thus,
a₂ = -3
a₃ = -1
Thus, the sequence becomes:
-5, -3, -3, 1
That would be 1 - 11/12 - 1/18 = 36/36 - 33/36 - 2/36 = 1/36 answer
Answer:
x = ± 2
Step-by-step explanation:
Given
f(x) = x² + 1 and (x, 5 ) is a solution then f(x) = 5
Equating the two gives
x² + 1 = 5 ( subtract 1 from both sides )
x² = 4 ( take the square root of both sides )
x = ±
= ± 2
Thus (- 2, 5) and (2, 5) are solutions
-23(3) + 1
-69 + 1
f(3)= -68