Answer:
The remainder would be 1 or 3
Step-by-step explanation:
Consider the 5 consecutive positive integers are,
x, x + 1, x + 2, x + 3, x + 4,
![Average =\frac{\text{Sum of all observation}}{\text{Number of observations}}](https://tex.z-dn.net/?f=Average%20%3D%5Cfrac%7B%5Ctext%7BSum%20of%20all%20observation%7D%7D%7B%5Ctext%7BNumber%20of%20observations%7D%7D)
Since, the average of these 5 numbers = ![\frac{x+x+1+x+2+x+3+x+4}{5}](https://tex.z-dn.net/?f=%5Cfrac%7Bx%2Bx%2B1%2Bx%2B2%2Bx%2B3%2Bx%2B4%7D%7B5%7D)
![=\frac{5x+10}{5}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B5x%2B10%7D%7B5%7D)
= x + 2
If x + 2 = odd,
⇒ x = odd - 2 = odd - even = odd
⇒ x + 4 = odd + even = odd
∵ an odd number is represented by '2n + 1'
Where, n = 0, 1, 2, 3, ........
Now, 2n + 1 = 1( mod 4) if n = even
While, 2n + 1 = 3( mod 4) if n = odd,
Hence, when the largest of the five integers is divided by 4 remainder would be 1 or 3.