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Nana76 [90]
3 years ago
10

The formula for the perimeter of rectangle is P=2L+2w, where L is the lenght and W is the width. A rectangle has a perimeter of

24 inches. Find its dimensions if its lenght is 3 inches greater than its width
Mathematics
1 answer:
shepuryov [24]3 years ago
3 0
P=2L+2W
L=3+w
24=2x(3+w)+2w
24=6+2w+2w
24=6+4w
24-6=4w
18=4w
4 and 1/2 = 2
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Place these numbers in order from greatest to least: <br> .27, 25%, 13/50, .274, 7/25, 30%
skad [1K]

Answer:27, 0.3, 7/25, 0.274, 13/50, 0.25

Step-by-step explanation:

6 0
3 years ago
Please answer this correctly
jeka57 [31]

Answer:

169.5 yd²

Step-by-step explanation:

See attachment.

In situations like this, ALWAYS (!) make as sketch.

Divide the areas by adding dotted lines on sensible places, and write in the missing numbers for the correct distances.

The only possible difficult one is the triangle, which is the half of a rectangle. So you are dealing with a series of areas of rectangles. That is really easy if you understand what you are doing.

Total area =

area 1 + area 2 + area 3 + area 4

10*4 + 4*7 + 3*13 + (0.5 * 7*17)

40 + 28 + 42 + 59.5

Total area = 169.5 yd²

6 0
3 years ago
8x-15 =3x how to do this
Greeley [361]
8x - 15 = 3x
     +15       +15
8x = 3x + 15
        -3x
5x = 15
/5        /5
x = 3
6 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=4x%20%7B%7D%5E%7B2%7D%20%20%2B%2020x%20%2B%2025" id="TexFormula1" title="4x {}^{2} + 20x + 25
BigorU [14]

\sf{\qquad\qquad\huge\underline{{\sf Answer}}}

Let's Solve ~

\qquad \sf  \dashrightarrow \: 4 {x}^{2}  + 20x + 25

\qquad \sf  \dashrightarrow \: 4 {x}^{2}  + 10x + 10x + 25

\qquad \sf  \dashrightarrow \: 2x(2x + 5) + 5(2x + 5)

\qquad \sf  \dashrightarrow \: (2x + 5) (2x + 5)

\qquad \sf  \dashrightarrow \: (2x + 5) {}^{2}

or

\sf{\qquad \sf  \dashrightarrow \: 4x² + 20x + 25 }

\sf{\qquad \sf  \dashrightarrow \: (2x)² + (2 \sdot 2x \sdot 5) + (5)²}

[ it's similar to expression - a² + 2ab + b² that is equal to (a + b)² ]

so, let's use this identity here to factorise :

\sf{\qquad \sf  \dashrightarrow \: (2x + 5)²}

I hope it was helpful ~

3 0
2 years ago
Please help me with math thanks
Korvikt [17]
Given that a room is shaped like a golden rectangle, and the length is 29 ft with the ratio of  golden rectangle being (1+√5):2, thus the width of the room will be:
ratio of golden triangle=(length if the room)/(width of the room)
let the width be x
thus plugging the values in the expression we get:
29/x=(1+√5)/2
solving for x we get:
x/29=2/(1+√5)
thus
x=(29×2)/(1+√5)
answer is:
x=58/(1+√5)
or
 byrationalizing the denominator by multiplying both the numerator and the denominator by (1-√5)
58/(1+√5)×(1-√5)/(1-√5)
=[58(1-√5)]/1-5
=(58√5-58)/4
7 0
3 years ago
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