Since AS is a height issued from A and the perpendicular bisector of [MP] at the same time (given), so the triangle AMP is an isosceles triangle of vertex A. Then, AM=AP
MS=SP ( AS bisects MP as stated in the given )
AS is a common side between triangles ASM and ASP
Therefore, triangles ASM and ASP are congruent (SSS)
Your answer is 4 radical 2.
This is called the median.
Answer:
the answer is 8.334
Step-by-step explanation:
Find the horizontal and vertical distance between the points. First, subtract y2 - y1 to find the vertical distance. Then, subtract x2 - x1 to find the horizontal distance.
