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zimovet [89]
3 years ago
13

Solve for this equation x/-6 (x over negative 6) = 11

Mathematics
1 answer:
stellarik [79]3 years ago
4 0
X/-6 = 11
X = 11 x -6
X = -66
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HELP ASAP!!!! 30 POINTS
Vedmedyk [2.9K]

Answer:

20.8 ft²

Step-by-step explanation:

area = (ab sin C)/2

area = (6 ft × 8 ft × sin 60°)/2

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6 0
2 years ago
What is the equation of the line passing through the point (4, 5) that is parallel to the line with the equation
Reptile [31]

Answer:

y=2x-3

Step-by-step explanation:

1. find the slope

6x-3y=21

-3y=-6x+21 divide both sides by -3

y=2x-7

slope is 2

2.y-5=2(x-4)

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PARALLEL lines have the same slope

7 0
3 years ago
Find the equation of the line.
Grace [21]

Answer:

m:-\frac{1}{3}

Step-by-step explanation:

Pick two points (0,5) and (3,4)

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Insert values: \frac{4-5}{3-0}

m:-\frac{1}{3}

:-)

7 0
3 years ago
Convert 27 cubits to fathoms
topjm [15]
27 cubits =
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5 0
3 years ago
The slope-intercept form of the equation of a line that passes through point (-3, 8) is y = -2/3x + 6. What is the point-
Elena-2011 [213]

y = \stackrel{\stackrel{m}{\downarrow }}{-\cfrac{2}{3}}x+6\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}

so hmmm then we know the slope of that line is -2/3, so we're really looking for the point-slope form of a line with a slope of -2/3 and that passes through (-3 , 8)

(\stackrel{x_1}{-3}~,~\stackrel{y_1}{8})\hspace{10em} \stackrel{slope}{m} ~=~ -\cfrac{2}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{8}=\stackrel{m}{-\cfrac{2}{3}}(x-\stackrel{x_1}{(-3)})\implies y-8=-\cfrac{2}{3}(x+3)

3 0
2 years ago
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