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3 years ago

How do you estimate the sum or difference of 6/10 + 7/12

Mathematics

1 answer:

Nataly [62]3 years ago

4 0

Well 6/10 is about 5/10 or 1/2 and 7/12 is about 6/12 or 1/2 so it will be about 1 as your answer

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What is the least common múltiple of 30 and 13

Crazy boy [7]

The least common multiple of 30 and 13 is 390 !

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3 years ago

Read 2 more answers

Which of the following is the solution set of x² + 8x + 12 = 0?

raketka [301]

Answer:

$\fbox{\begin{minipage}{9em}x = -2 and x = -6\end{minipage}}$

Step-by-step explanation:

Given:

$x^{2} + 8x + 12 = 0$

Solve for:

$x$

Solution:

Step 1: Select the formula to solve for $x$

There are some ways to solve quadratic equations.

One of the simple way (if possible) is performing the factorization.

Another way is using the quadratic formula.

Here, we are going to use factorization.

Step 2: Perform factorization

$x^{2} + 8x + 12 = 0$

<=> $x^{2} + 2x + 6x + 12 = 0$

<=> $(x^{2} + 2x) + (6x + 12) = 0$

<=> $x(x + 2) + 6(x + 2) = 0$

<=> $(x + 2)(x + 6) = 0$

<=> $x = -2$ or $x = -6$

Hope this helps!

4 0

3 years ago

in a classroom 1/6 of the students are wearing blue shirts, ans 2/3 are wearing white shirts. There ade 36 students in the class

castortr0y [4]

56 should be correct

4 0

3 years ago

HElP!

zheka24 [161]

Answer:

A- The cabinets have the same base area.

C- The cabinets may have the same base dimensions.

D- The cabinets may have different base dimensions

Step-by-step explanation:

4 0

4 years ago

Assume that when adults with smartphones are randomly selected, 54% use them in meetings or classes (based on data from an lg sm

GuDViN [60]

Answer: 0.951%

Explanation:

Note that in the problem, the scenario is either the adult is using or not using smartphones. So, we have a yes or no scenario involved with the random variable, which is the number of adults using smartphones. Thus, the number of adults using smartphones follows the binomial distribution.

Let x be the number of adults using smartphones and n be the number of randomly selected adults. In Binomial distribution, the probability that there are k adults using smartphones is given by

$P(x = k) = \frac{n!}{k!(n-k)!}p^k (1-p)^{n-k}$

Where p = probability that an adult is using smartphones = 54% (since 54% of adults are using smartphones).

Since n = 12 and k = 3, the probability that fewer than 3 are using smartphones is given by

$P(x \ \textless \ 3) = P(x = 0) + P(x = 1) + P(x = 2)
\\ \indent = \frac{12!}{0!(12-0)!}(0.54)^0 (1-0.54)^{12-0} + \frac{12!}{1!(12-1)!}(0.54)^1 (1-0.54)^{12-1} + \\ \indent \frac{12!}{2!(12-2)!}(0.54)^2 (1-0.54)^{12-2}
\\
\\ \indent = \frac{12!}{(1)(12!)}(0.46)^{12} + \frac{12(11!)}{(1)(11!)}(0.54)(0.46)^{11}+ \frac{12(11)(10!)}{(2)(10!)}(0.54)^2(0.46)^{10}
\\
\\ \indent = (1)(0.46)^{12} + (12)(0.54)(0.46)^{11}+ (66)(0.54)^2(0.46)^{10}
\\ \indent \boxed{P(x \ \textless \ 3) \approx 0.00951836732 }
$

Therefore, the probability that there are fewer than 3 adults are using smartphone is 0.00951 or 0.951%.

5 0

4 years ago

How do you estimate the sum or difference of 6/10 + 7/12​

How do you estimate the sum or difference of 6/10 + 7/12