The answer is $3,960
you multiply 220,000 by 0.03 to get the amount the broker takes which is $6,600
you then multiply 6,600 by 0.60 to get the amount the agent receives, being $3,960
Forms for the equation of a straight line
Suppose that we have the graph of a straight line and that we wish to find its equation. (We will assume that the graph has x and y axes and a linear scale.) The equation can be expressed in several possible forms. To find the equation of the straight line in any form we must be given either:
two points, (x1, y1) and (x2, y2), on the line; or
one point, (x1, y1), on the line and the slope, m; or
the y intercept, b, and the slope, m.
In the first case where we are given two points, we can find m by using the formula:
Once we have one form we can easily get any of the other forms from it using simple algebraic manipulations. Here are the forms:
1. The slope-intercept form:
y = m x + b.
The constant b is simply the y intercept of the line, found by inspection. The constant m is the slope, found by picking any two points (x1, y1) and (x2, y2) on the line and using the formula:
2. The point-slope form:
y − y1 = m (x − x1).
(x1, y1) is a point on the line. The slope m can be found from a second point, (x2, y2), and using the formula:
3. The general form:
a x + b y + c = 0.
a, b and c are constants. This form is usually gotten by manipulating one of the previous two forms. Note that any one of the constants can be made equal to 1 by dividing the equation through by that constant.
4. The parametric form:
Yea so you include $12 for him getting in the clinic and then 30-12=18
And divide 3 and 18
So 6!
So he can have 6 buckets!
Answer:
the z score is 25
Step-by-step explanation:
since 75 needs 25 more for and 100%
Answer:
C
Step-by-step explanation:
To determine which point lies on the graph, substitute the x-coordinate into f(x) and if the value is equal to the y-coordinate then the point is on the graph
A (15, 1)
f(15) = 3 × 
≠ 1 ← not on graph
B (0, 15)
f(0) = 3 × 
= 3 × 1 = 3 ≠ 15 ← not on graph
C (1, 15)
f(1) = 3 × 
= 3 × 5 = 15 ← lies on graph
D (0, 0)
f(0) = 3 × = 3 × 1 = 3 ≠ 0 ← not on graph
