Question

the marine-life store would like to set up fish tanks that contain equal numbers of angel fish, swordtails, and guppies. what is the greatest number of tanks that can be set up if the store has 12 angel fish, 24 swordfish, and 30 guppies?

Answer 1

6 tanks
12 / 6 = 2
24/ 6 = 4
30 / 6 = 5

Answer 2

Answer:  6

Step-by-step explanation:

Given : The marine-life store would like to set up fish tanks that contain equal numbers of angel fish, swordtails, and guppies.

The store has 12 angel fish, 24 swordfish, and 30 guppies.

Then, the greatest number of tanks that can be set up will be the greatest common factor of 12, 24 and 30.

Prime factorization of 12, 24 and 30 :

$12=2\times2\times3\\\\24=2\times2\times2\times3\\\\30=2\times3\times5$

Then, Greatest common factor of 12, 24 and 30=$2\times3=6$

Hence, the greatest number of tanks that can be set up will be 6.