Answer:
107 in ²
Step-by-step explanation:
Surface area of the triangular prism = bh + L(s1 + s2 + s3)
Where,
b = 2 in.
h = 8 in.
s1 = 8.2 in.
s2 = 2 in.
s3 = 8 in.
L = 5 in.
Substitute
Surface area = 2 × 8 + 5(8.2 + 2 + 8)
Surface area = 16 + 5(18.2)
Surfaces area = 16 + 91
Surface area = 107 in ²
The answer is 100 because 128 is closest to 100. in order for it to be 200, it has to be over 150
Answer:
Step-by-step explanation:
In ΔABC, we have,
∠B=2∠C or ∠B=2y where ∠C=y
AD is the bisector of ∠BAC. So, Let ∠BAD=∠CAD=x
Let BP be the bisector of ∠ABC.
In ΔBPC, we have
∠CBP = ∠BCP = y ⇒ BP = PC ... (1)
Now, in ΔABP and ΔDCP, we have
∠ABP = ∠DCP = y
AB = DC [Given]
and, BP = PC [Using (1)]
So, by SAS congruence criterion, we have
Δ ABP ≅ Δ DCP
Therefore
∠BAP = ∠ CDP = 2x and AP = DP ,
So in Δ APD, AP=DP
=> ∠ADP = ∠DAP = x
In ΔABD, we have
∠ADC = ∠ABD + BAD ⇒ 3x= 2y + x
⇒ x = y
In ΔABC, we have
∠A + ∠B + ∠C = 180°
⇒ 2x + 2y + y = 180°
⇒ 5x = 180°
⇒ x = 36°
Hence, ∠BAC = 2x = 72°
Answer: No
Step-by-step explanation: For 57 to be a prime number, it would have been required that 57 has only 2 divisors, ie itself and 1. How ever 57 is a semiprime because it is the product of a two non- necessarily distinct prime numbers. inderd, 57= 3×19, where 3 and 19 are prime numbers.
Answer:
B and C
Step-by-step explanation:
Required
Select graphs that are dilated by a scale factor greater than 1
For graph A:
Graph A is smaller than the original graph. This indicates dilation with a scale factor less than 1
For graph B:
Graph B is bigger than the original graph and is dilated over (0,0). This indicates dilation with a scale factor greater than 1
For graph C:
Graph C is bigger than the original graph; however, it is not dilated over (0,0). This indicates dilation with a scale factor greater than 1
For graph D:
Graph D is bigger than the original graph; however, it is not only dilated but also flipped over (i.e. rotated).
<em>Hence, b and c is true</em>