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maksim [4K]
3 years ago
5

How would you write sixteen and twenty-five hundredths with a decimal

Mathematics
2 answers:
kifflom [539]3 years ago
6 0
The answer is 16.25
OLga [1]3 years ago
3 0
You would write it like 16.25
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What is the value of x?
fenix001 [56]

Answer:

B, x=5

Step-by-step explanation:

Both triangles are similar with a ratio of 22.5/9

so using that an equation can be created like this, \frac{22.9}{9} = \frac{23.5}{x+4.4}

If simplified, 22.9(x + 4.44) = 23.5(9)

22.5x + 99 = 211.5

22.5x = 112.5

<u><em>x = 5</em></u>

8 0
3 years ago
The fish tank in Paul's bedroom has a pump that will recirculate 75 gallons of water in 1/4 of an hour. Find the unit rate in ga
m_a_m_a [10]
We know that
(1/4) hour---------> 0.25 hour
if the pump r<span>ecirculate 75 gallons of water in -------------> 0.25  hour
 X </span>gallons of water in-----------------------------------------> 1 hour

X=75/0.25----------> x=300 gallons /hour

the answer is 300 gallons /hour
6 0
3 years ago
Use the frequency distribution, which shows the number of American voters (in millions) according to age, to
a_sh-v [17]

Answer:

The probability that a voter chosen at random is in the 18 to 20 years old age range is =  4.2/ 134.8= 0.0311572

Step-by-step explanation:

We can find the probability by simply dividing the frequency of the ages range of 18-20 by the total frequency.

Ages                Frequency

18 to 20             4.2

21 to 24             7.8

25 to 34           20.8

35 to 44           23.7

45 to 64           50.1

<u>65 and over       28.2</u>

<u>∑                        134.8</u>

The probability of an event is given by the occurrence of an event by the total occurrences .

So

Here the occurrence of ages 18-20 is given by 4.2

and the total frequency is 134.8

The probability that a voter chosen at random is in the 18 to 20 years old age range is =  4.2/ 134.8= 0.0311572

7 0
4 years ago
A study claims that college students spend an average of 4 hours or less studying per day. A researcher wants to check if this c
kirill115 [55]
<h2>Answer with explanation:</h2>

Let \mu be the population mean.

By observing the given information, we have :-

H_0:\mu\leq4\\\\H_a:\mu>4

Since the alternative hypotheses is left tailed so the test is a right-tailed test.

We assume that the time spend by students per day is normally distributed.

Given : Sample size :  n=121 , since n>30 so we use z-test.

Sample mean : \overline{x}=3.15

Standard deviation : \sigma=1.2

Test statistic for population mean :-

z=\dfrac{\overline{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}

\Rightarrow\ z=\dfrac{3.15-4}{\dfrac{1.2}{\sqrt{121}}}\\\\\Rightarrow\ z=-7.79166666667\approx-7.79

Critical value (one-tailed) corresponds to the given significance level :-

z_{\alpha}=z_{0.1}=1.2816

Since the observed value of z (-7.79) is less than the critical value (1.2816) , so we do not reject the null hypothesis.

Hence, we conclude that we have enough evidence to accept that the college students spend an average of 4 hours or less studying per day.

4 0
3 years ago
Find the mean absolute deviation (MAD) of the data in the pictograph below
mezya [45]

Answer:

16

Step-by-step explanation:

4 0
4 years ago
Read 2 more answers
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