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2 years ago

Which fraction is equivalent to negative 4 over 6?

Mathematics

2 answers:

Ksenya-84 [330]2 years ago

6 0

Answer:

Step-by-step explanation:

The answer is 4 over negative 6 is equal to negative four over six.

hope this helps.

tangare [24]2 years ago

3 0

Answer:

negative 8 over 12, negative 12 over 18, negative 16 over 24 and so on

Step-by-step explanation: Equivalent fractions are generated by multiplying the numerator and denominator by the same number. :) Hope this helps!

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How do i Solve: 3x2−6x−12=0 ?

MrMuchimi

Answer:

1 + root 5, 1 - root 5

Step-by-step explanation:

I assume you mean 3x^2-6x-12=0.

First, note that you can divide both sides by 3. You get:

x^2-2x-4=0

Use the quadratic equation.

$x=\frac{2\pm\sqrt{4+16}}{2}=\frac{2\pm2\sqrt{5}}{2}=1\pm\sqrt{5}$

Therefore, x=1 + root 5, 1 - root 5

4 0

2 years ago

The data to represent average test scores for a class of 16 students includes an outlier value of 78. If the mean, including the

monitta

Answer:

Given that The data to represent average test scores for a class of 16 students includes an outlier value of 78.

We can find sum of all 16 test scores = 84(16) = 1344

Outlier found = 78

If outlier is removed new sum = 1344-78 = 1266

Number of entries without outlier = 15

New average = 1266/12 =84.4

We find that average of new data increases.

Also whenever we remove outlier std deviation also would be reduced.

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

∠A=6x−18 ∘ start color #11accd, angle, A, end color #11accd, equals, start color #11accd, 6, x, minus, 18, degrees, end color #1

denpristay [2]

Using the properties of alternate angles, the value of x = 8 and ∠ A = 30

<h3>What are Alternate Angles?</h3>

A transversal that crosses two parallel lines produces alternate exterior angles. They form two pairs (four total angles) of alternate outside angles since they are situated "outside" the two parallel lines but on different sides of the transversal.

For the given question,

∠A=6x−18

∠B=14x+38

As, both parallel lines are intersected by a transversal,

the value of angle ∠A and ∠180 - B is same as they are alternate angles,

⇒ 6x−18 = 180 - 14x - 38

⇒ 6x + 14x = 142 + 18

⇒ 20x = 160

⇒ x = 8

∠A = 6x−18

⇒ ∠ A = 30

To learn more abut alternate angles from given link