Answer:
130.8
Step-by-step explanation:
i just think that you times 0.40 and 327 and then press = and it should give you 130.8
i hope it works
Answer:
6x ≥ 3 + 4(2x - 1)
⇔ 6x ≥ 3 + 8x - 4 => remove the parentheses
⇔ 6x - 8x ≥ 3 - 4
⇔ -2x ≥ -1
⇔ 2x ≤ 1 (or 1 ≥ 2x)
⇔ x ≤ 1/2
⇔ x ≤ 0.5
The answer for the question should be:
1 ≥ 2x
6x ≥ 3 + 8x – 4
and the first graph.
Answer:
bxc+ax32=0
Step-by-step explanation:
46 -2c
46 decreased by means 46 minus
Twice c would be c times 2
Answer:
a) 30 kangaroos in 2030
b) decreasing 8% per year
c) large t results in fractional kangaroos: P(100) ≈ 1/55 kangaroo
Step-by-step explanation:
We assume your equation is supposed to be ...
P(t) = 76(0.92^t)
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a) P(10) = 76(0.92^10) = 76(0.4344) = 30.01 ≈ 30
In the year 2030, the population of kangaroos in the province is modeled to be 30.
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b) The population is decreasing. The base 0.92 of the exponent t is the cause. The population is changing by 0.92 -1 = -0.08 = -8% each year.
The population is decreasing by 8% each year.
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c) The model loses its value once the population drops below 1/2 kangaroo. For large values of t, it predicts only fractional kangaroos, hence is not realistic.
P(100) = 75(0.92^100) = 76(0.0002392)
P(100) ≈ 0.0182, about 1/55th of a kangaroo
