Question

In a​ lottery, 6 numbers are randomly sampled without replacement from the integers 1 to 38. Their order of selection is not important. Find the probability of holding a ticket that has zero winning numbers out of the 6 numbers selected for the winning ticket out of the 38 possible numbers.

Answer 1

Answer: Our required probability is 0.328.

Step-by-step explanation:

Since we have given that

there is number on the lottery is from 1 to 38.

6 numbers are selected.

We need to find the probability of holding a ticket that has zero winning numbers out of the 6 numbers selected for the winning ticket.

So, it should be other than 6 numbers.

Remaining numbers = 38-6 = 32

So, our probability becomes

$\dfrac{^{32}C_6}{^{38}C_6}\\\\=\dfrac{906192}{2760681}\\\\=0.328$

Hence, our required probability is 0.328.