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4 years ago

Select the equation of the line parallel to 2x + 6y = -4 the equation and that passes through the point (3, -3) .

Mathematics

1 answer:

vagabundo [1.1K]4 years ago

4 0

Answer:

$\displaystyle x + 3y = -6$

Step-by-step explanation:

Plugging these coordinates into this equation will give you this:

3 - 9 = −6 ☑

* This is a genuine statement.

I am joyous to assist you anytime.

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Which algebraic expression is a trinomial?

tangare [24]

Answer:

D. x^6 - x + √6

Step-by-step explanation:

Last option:

⇒ x^6 - x + √6

Cannot be simplified further and has three terms.

Therefore is a trinomial.

7 0

2 years ago

The double number line shows that 4 pounds of tomatoes cost $14. Draw tick marks and write labels to show the prices of 1, 2, an

RUDIKE [14]

Answer:

each tick is 3.50

Step-by-step explanation:

14/4=3.5

hope dis helps \_)0___0)_/

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4 years ago

Fifteen Players , 2 coaches , anf 21 parents attened this year's sports banquey. The cost of each meal was $12.00 plus 5% (0.05)

Arte-miy333 [17]

$34.80 because, if you add 15+2+21=58x12.00=696x0.05=34.80

6 0

3 years ago

Which expression would be equivalent to: Which expression would be equivalent to: \frac{1+b}{2} - 3(a-1)

IrinaVladis [17]

Answer:

$\frac{1+b}{2} - 3(a-1) = \frac{b- 6a+7}{2}$

Step-by-step explanation:

Given

$\frac{1+b}{2} - 3(a-1)$

Required

An equivalent expression

$\frac{1+b}{2} - 3(a-1)$

Take LCM

$\frac{1+b}{2} - 3(a-1) = \frac{1+b- 2*3(a-1)}{2}$

$\frac{1+b}{2} - 3(a-1) = \frac{1+b- 6(a-1)}{2}$

Open bracket

$\frac{1+b}{2} - 3(a-1) = \frac{1+b- 6a+6}{2}$

Collect like terms

$\frac{1+b}{2} - 3(a-1) = \frac{b- 6a+6+1}{2}$

$\frac{1+b}{2} - 3(a-1) = \frac{b- 6a+7}{2}$

Hence, an equivalent expression is:

$\frac{b- 6a+7}{2}$

8 0

3 years ago

Which of the following illustrates a phase shift?

Natasha_Volkova [10]

Answer:

A. y = -2 - cos(x-π)

Explanation:

The general form of the trig equation is:

y = A sin (Bx + C) + D

where:

A is the amplitude

$\frac{2\pi}{B}$ is the period

$\frac{-C}{B}$ is the phase shift

D is the vertical shift

Now, let's check the choices:

A. y = -2 - cos(x-π)

$\frac{-C}{B} = \frac{\pi}{1} = \pi$

Therefore, the function has a phase shift of π

B. y = 3 cos(4x)

$\frac{-C}{B} = \frac{0}{4} = 0$

Therefore, the function has no phase shift

C. y = tan(2x)

$\frac{-C}{B} = \frac{0}{2} = 0$

Therefore, the function has no phase shift

D. y = 1 + sin(x)

$\frac{-C}{B} = \frac{0}{1} = 0$

Therefore, the function has no phase shift

Based on the above, the correct answer is A

Hope this helps :)

3 0

3 years ago

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