2 years ago

Cedric and Insha solved the same equation using the calculations below.

Mathematics

1 answer:

Mariulka [41]2 years ago

3 0

The first working out is correct, z = 3

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$Use:\\\\\dfrac{a^n}{a^m}=a^{n-m}\\\\(a^n)^m=a^{nm}\\\\a^{-n}=\dfrac{1}{a^n}\\\\(ab)^n=a^nb^n$

$\left(\dfrac{a^{-3}b}{a^{-5}b^3}\right)^{-3}=\left(a^{-3-(-5)}b^{1-3}\right)^{-3}=\left(a^{-3+5}b^{-2}\right)^{-3}=\left(a^2b^{-2}\right)^{-3}\\\\=(a^2)^{-3}(b^{-2})^{-3}=a^{2(-3)}b^{-2(-3)}=a^{-6}b^6=\dfrac{b^6}{a^6}$

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Answer:

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Step-by-step explanation:

Function notation is a way of converting a written description of a function to a concise form that is easy to read.

It is another way of representing the y-value in a function, y = ƒ(something)

Let's convert the word expression to function notation:

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y = a(h)

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Step-by-step explanation:

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Step-by-step explanation:

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