Considering 32 outside the square root .
![(8+5 \sqrt x -98) -(3+6\sqrt x-32)](https://tex.z-dn.net/?f=%20%288%2B5%20%5Csqrt%20x%20-98%29%20-%283%2B6%5Csqrt%20x-32%29%20)
Here we have to combine like terms, and like terms are 8 , 98 ,3, 32 and 5 square root x and 6 square root x .
We need to remove the parenthesis and since there is a minus sign outside the second parenthesis , so we have to flip the sign of the terms of second parenthesis. THat is
![8-98-3+32+5 \sqrt x -6 \sqrt x](https://tex.z-dn.net/?f=%208-98-3%2B32%2B5%20%5Csqrt%20x%20-6%20%5Csqrt%20x%20)
=![-61 - \sqrt x](https://tex.z-dn.net/?f=%20-61%20-%20%5Csqrt%20x%20)
And that's the final answer .
Answer:
half of the atoms of an unstable isotope to go through radioactive decay. ... amount of a sample will be left after a certain amount of time, or it can tell us how long has ... If the sample contained 510 grams, how much chromium would remain ... 5) Titanium-51 decays with a half-life of 6 minutes. ... How many grams of bismuth-.
Step-by-step explanation:
Answer:
It would be $465 marked up.
Step-by-step explanation:
55% of 300 is 165.
So marked up its 465 and marked down its 135.
Cool I don’t really know the answer sorry.
Answer:hold up
Step-by-step explanation: