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egoroff_w [7]
3 years ago
5

An acute angle θ is in a right triangle with sin θ = six sevenths. What is the value of cot θ?

Mathematics
2 answers:
DaniilM [7]3 years ago
8 0

Consider right triangle ABC with leg BC=6, hypotenuse AB=7 and angle C such that \sin \angle A=\dfrac{6}{7}.

By the Pythagorean theorem, you can find the length of the second leg AC:

AC^2+BC^2=AB^2,\\AC^2+36=49,\\AC^2=13,\\AC=\sqrt{13}.

Use the definition of \cot:

\cot \angle A=\dfrac{\text{adjacent leg}}{\text{opposite leg}}=\dfrac{AC}{BC} =\dfrac{\sqrt{13}}{6}.

Answer: \cot \theta=\dfrac{\sqrt{13}}{6}.

inysia [295]3 years ago
4 0
\sin \theta =\dfrac{6}{7}\\
\cot \theta=\dfrac{x}{6}\\
x^2+6^2=7^2\\
x^2=49-36\\
x^2=13\\
x=\sqrt{13}\\
\boxed{\cot \theta =\dfrac{\sqrt{13}}{6}}
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