PLEASE SHOW WORK I WILL GIVE BRAINLIEST!!! x-2y-2z=2 5x+2y-4z=-2 -5y-5z=0

Mathematics

1 answer:

mafiozo [28]3 years ago

7 0

Step-by-step explanation:

lets separate z from each equation

2z=x-2y-2

4z=5x+2y+2

5z=-5y

z=x/2-y-1

z=5x/4+y/2+1/2

z=-y

lets use the first and third equation

we have z=-y we replace this z at the first equation

-y=x/2-y-1 so x/2-1=0

x/2=1

x=2

now we replace z=-y and x=2 at the second equation so

-y=5*2/4+y/2+1/2

-y/2-y=5/2+1/2

-3y/2=6/2

-3y/2=3

-y/2=1

y=-2

we know that z=-y

so z =-(-2)=2

finaly we have that

x=2 ,y=-2 ,z=2

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Solve each equation by graphing the related function. If th equation has no real number solution, write no solution. X^2 + 7 = 0

Brrunno [24]

Answer:
The equation x² + 7 = 0 has no solution

Explanation:
1- using graph:
To solve the equation means graphically means to find the x-intercepts.
The attached image shows the graph of the given function.
We can note that there are no x-intercepts. This means that the given function has no real solutions

2- using algebra:
To solve the equation algebraically means to find the values of x that would make the equation equal to zero.
Solving the given equation, we would find that:
x² + 7 = 0
x² = -7
x = <span>± </span>√-7
The square root of a negative number will always give imaginary values. This means that the equation has no real solutions

Hope this helps :)