<em>BD</em> = 56
Step-by-step explanation:
Step 1: In rectangle, the diagonals are congruent and bisect each other.
So, <em>AC</em> = <em>BD</em>
⇒<em>AG</em> + <em>GC</em> = <em>BG</em> + <em>GD</em>
⇒<em>AG</em> + <em>AG</em> = <em>GD</em> + <em>GD</em>
⇒ 2<em>AG</em> = 2<em>GD</em>
⇒<em>AG</em> = <em>GD</em>
⇒ –7<em>j </em>+ 7 = 5<em>j</em> + 43
⇒–7<em>j</em> – 5<em>j</em> = 43 – 7
⇒–12<em>j</em> = 36
⇒<em>j</em> = –3
Step 2: <em>BD</em> = 2<em>DG</em>
<em>BD</em> = 2(5<em>j</em> + 43)
= 2(5 (–3) + 43)
= 2(–15 + 43)
= 2 × 28
= 56
Hence, <em>BD</em> = 56.
Answer:
(x -4)^2 +(y +5)^2 = 2
Step-by-step explanation:
The equation of a circle centered at (h, k) through point (p, q) is ...
(x -h)^2 +(y -k)^2 = (p -h)^2 +(q -k)^2
Filling in your given numbers gives ...
(x -4)^2 +(y +5)^2 = (5-4)^2 +(-4+5)^2
(x -4)^2 +(y -5)^2 = 2
Domain: [1 ; 6]
Range: [1 ; 7]
