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4 years ago

Which expression below has the same value as X3

Mathematics

1 answer:

Tpy6a [65]4 years ago

4 0

A.3x
When a variable is stuck next to a number you multiply.

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David drives 40 miles in one hour. How many miles does he drive 1.5 hours?

Karo-lina-s [1.5K]

Answer: 60 miles

Step-by-step explanation: if 40-20=20 and your trying to figure out how many miles is traveled in 1.5 miles then you add 40 and 20 which gives you 60 miles

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3 years ago

Answers for the 2 boxes please :)

Ulleksa [173]

Step-by-step explanation:

2x - 3y = 25

+ (5x + 3y = 10)

=> 7x = 35, x = 5.

Therefore 2(5) - 3y = 25, 3y = -15, y = -5.

The solution pair is (5,-5).

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3 years ago

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Please help, basic Algebra question

Tju [1.3M]

Answer:

The given expression $(\frac{5}{6} a^{9}p^{5}) ^{3} = \frac{125}{216} \times a^{(27) } \times p^{(15)}$

Step-by-step explanation:

Here, the given expression is: $(\frac{5}{6} a^{9}p^{5}) ^{3}$

Now, starting from the outer most bracket.

As we know :

$(abc)^{n} = (a)^{n} \times (b)^{n} \times (c)^{n}$

and $(a^m)^{n} = a^{(m \times n)}$

⇒ $(\frac{5}{6} a^{9}p^{5}) ^{3} = (\frac{5}{6})^{3} \times (a^{9})^{3} \times (p^{5}) ^{3}\\$

$=\frac{125}{216} \times (a)^{(9\times3) } \times (p)^{(5 \times 3)}\\= \frac{125}{216} \times a^{(27) } \times p^{(15)}$

Hence, the given expression $(\frac{5}{6} a^{9}p^{5}) ^{3} = \frac{125}{216} \times a^{(27) } \times p^{(15)}$

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3 years ago

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Lady_Fox [76]

Answer:

Step-by-step explanation:

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olchik [2.2K]

A bi-millennium means two (bi) times thousand of years (millenium), this means that a bi millennium has 2000 years in it: two thousand years.

The origin of this word is latin: because of this it also has the plural of "bimillennia" <span />

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4 years ago