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3 years ago

Factor the following polynomial 9x2 + 21x – 18

Mathematics

2 answers:

solong [7]3 years ago

4 0

Answer:

factors are

21 and x

Step-by-step explanation:

equation 9 × 2 + 21x - 18

terms 9 , 2, 21x, -18

factors 21x = 21 and x

Elena L [17]3 years ago

3 0

Answer:

3(x + 3)(3x - 2)

Step-by-step explanation:

Given

9x² + 21x - 18 ← factor out 3 from each term

= 3(3x² + 7x - 6) ← factor the quadratic

Consider the factors of the product of the x² term and the constant term which sum to give the coefficient of the x- term

product = 3 × - 6 = - 18 and sum = + 7

The factors are + 9 and - 2

Use these factors to split the x- term

3x² + 9x - 2x - 6 ( factor first/second and third/fourth terms )

3x(x + 3) - 2(x + 3) ← factor out (x + 3) from each term

(x + 3)(3x - 2)

Then

9x² + 21x - 18 = 3(x + 3)(3x - 2) ← in factored form

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nydimaria [60]

Answer:

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Step-by-step explanation:

Given

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Required

Determine $\tan(\theta) \cdot \cot(\theta) + \csc(\theta)$

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So:

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Rationalize

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So, we have:

$\tan(\theta) \cdot \cot(\theta) + \csc(\theta)$

$\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = \tan(\theta) \cdot \frac{1}{\tan(\theta)} + \csc(\theta)$

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Substitute: $\csc(\theta) = \frac{-3\sqrt 5}{5}$

$\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = 1 -\frac{3\sqrt 5}{5}$

Take LCM

$\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = \frac{5 - 3\sqrt 5}{5}$

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