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Sergio039 [100]
3 years ago
5

Marlon withdrew $25 from his savings account every week for 5 weeks. Which expression is the best choice to help him determine t

he total amount of money he withdrew? (5 points)
Group of answer choices

(25)(−5) = −125; he withdrew $125

(−25)(5) = −125; he withdrew $125

(−25)(−5) = 125; he withdrew $125

(25)(5) = 125; he withdrew $125
Mathematics
1 answer:
leva [86]3 years ago
8 0
(25)(5)=125; he withdrew $125
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Answer:

1) vertical line test

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3 years ago
Brienne and 3 friends bought tickets to the movies. They spent a total of $27.00 on the tickets. Which equation represents this
Sindrei [870]
Hello!

The equation that represents this situation is A. 3t = 27.

Explanation:

This is because an equation is a "mathematical sentence" and this equation says that if you multiply the costs of the three friends' tickets, the total cost would be $27.
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3 years ago
A construction company is considering submitting bids for contracts of three different projects. The company estimates that it h
julsineya [31]

Answer:

a.P(x)=\frac{n!}{x!(n-x)!}*p^{x}*(1-p)^{n-x}\\

b. E(x) = 0.3

c. S(x)=0.5196

d. E=5,000

Step-by-step explanation:

The probability that the company won x bids follows a binomial distribution because we have n identical and independent experiments with a probability p of success and (1-p) of fail.

So, the PMF of X is equal to:

P(x)=\frac{n!}{x!(n-x)!}*p^{x}*(1-p)^{n-x}\\

Where p is 0.1 and it is the chance of winning. Additionally, n is 3 and it is the number of bids. So the PMF of X is:

P(x)=\frac{3!}{x!(3-x)!}*0.1^{x}*(1-0.1)^{n-x}\\

For binomial distribution:

E(x)=np\\S(x)=\sqrt{np(1-p)}

Therefore, the company can expect to win 0.3 bids and it is calculated as:

E(x) = np = 3*0.1 = 0.3

Additionally, the standard deviation of the number of bids won is:

S(x)=\sqrt{np(1-p)}=\sqrt{3(0.1)(1-0.1)}=0.5196

Finally, the probability to won 1, 2 or 3 bids is equal to:

P(1)=\frac{3!}{1!(3-1)!}*0.1^{1}*(1-0.1)^{3-1}=0.243\\P(2)=\frac{3!}{2!(3-2)!}*0.1^{2}*(1-0.1)^{3-2}=0.027\\P(3)=\frac{3!}{3!(3-3)!}*0.1^{3}*(1-0.1)^{3-3}=0.001

So, the expected profit for the company is equal to:

E=-10,000+50,000(0.243)+100,000(0.027)+150,000(0.001)\\E=5,000

Because there is a probability of 0.243 to win one bid and it will produce 50,000 of income, there is a probability of 0.027 to win 2 bids and it will produce 100,000 of income and there is a probability of 0.001 to win 3 bids and it will produce 150,000 of income.

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3 years ago
Alex has 7 pounds of birdseed and 5 bird feeders.
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Well, we dont know because we cant see the barmodels
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The correct answer 1519.8 feet^2
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