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MatroZZZ [7]
3 years ago
11

Dianna has 6 quarters, 5 dimes, and 4 nickels in her purse. She reaches into her purse and randomly grabs two coins. What is the

probability that Dianna grabs two dimes?
A. 1/9
B. 4/45
C. 5/52
D. 2/21
Mathematics
1 answer:
777dan777 [17]3 years ago
4 0
The correct answer is B: 4/45


reasoning:

how to get the answer is simple. first you have to find a common factor. the only common factor in this chart of 15 is 45. even from then you have an obvious answer and can eliminate all other possible answers. :)
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Answer:

The probability that the dogs are blue eyed and deaf is 13.02%.

Step-by-step explanation:

We are given the following information in the question:

P(Blue eyes) = 31%

P(Deaf) = 38%

P(Deaf | Blue eyes) = 42%

Formula for conditional probability:

P( A|B) = \displaystyle\frac{P(A \cap B)}{P(B)}

Now, let A be the event where the dog is deaf and B be the the event where dog is blue eyed.

P( \text{ Deaf}|\text{Blue eyes}) = \displaystyle\frac{P( \text{Deaf} \cap \text{Blue eyes})}{P(\text{Blue eyes})}\\\\0.42 = \displaystyle\frac{P( \text{Deaf} \cap \text{Blue eyes})}{0.31}\\\\P( \text{Deaf} \cap \text{Blue eyes}) = 0.42\times 0.31 = 0.1302 = 13.02\%

Hence, the probability that the dogs are blue eyed and deaf is 13.02%.

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216

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36 times 10 = 360

360 times 0.60  = 216

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