John will pay $8.68 for the combined cost of 1 pound of banana and 1 pound of cherries.
Let: b=cost of banana per pound and c=cost of cherries per pound
Equation 1: For 3 pounds of cherries and 2 pounds of bananas, John pays a total of $24.95.
3c + 2b =$24.95
Equation 2: The cost of bananas is $6.50 less than a pound of cherries.
b= c - $6.50
We can substitute the second equation into the first one to solve for the cost of cherries per pound.
3c + (2)(c-$6.50)= $24.95
3c + 2c -$13.00 = $24.95
5c = $24.95 + $13.00
c = $7.59
Substituting the value of c to the second equation to solve for b.
b= $7.59 - $6.50 = $1.09
The combined cost of 1 pound of banana and 1 pound of cherries is $1.09 + $7.59 or $8.68.
For more information regarding the system of equations, please refer to brainly.com/question/25976025.
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Answer:
A
Step-by-step explanation:
Qué es?
<span> <span>A.</span>Es una grapadora.</span><span> <span>B.</span>Es una puerta.</span><span> <span>C.</span>Es un mapa.</span><span> <span>D.</span><span>Es un cartel.</span></span>
An = A1 + (N-1)d
A1 is the first term (in this case 2)
d is the common difference (what is the difference between all consecutive even numbers? 2)
N is the number of terms to find (in this case 29)
An = 2 + (29-1)2 = 58
I would say none of the above, unless you typed it wrong. The sum is the product of the number of terms minus one and two, plus two more. So it's almost answer B but not really. Good luck with this one.
<span>2x^2 + 3x + 5 = 0
a = 2 b = 3 and c = 5
x = [-b +-sq root(b^2 -4ac)] / 2a
</span><span>x = [-3 +-sq root(9 -4*2*5)] / 4
x = [-3 +-sq root(9 - 40)] / 4
</span><span>x = -(3 / 4) + sq root (-36) / 4
</span><span>x = -(3 / 4) - sq root (-36) / 4
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